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3 years ago

1. A 59 kg person is in a vehicle travelling at 41 m/s. The vehicle runs into a telephone pole. At impact, it

Physics

1 answer:

Tems11 [23]3 years ago

5 0

Answer:

a. 12,600 N

b. 1290 kg

Explanation:

a. Impulse = change in momentum

F Δt = m Δv

F (0.192 s) = (59 kg) (0 m/s − 41 m/s)

F = -12,600 N

b. F = mg

12,600 N = m (9.8 m/s²)

m = 1290 kg (or 2,830 lbs)

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A beam oflight is reflected off a mirror. If the angle of incidence is 30 degrees, according to the Law of Reflection the angle

zaharov [31]

Answer:

30°

Explanation:

According to the second law of reflection, it States that the angle of incidence i is equal to the angle of reflection r.

The angle of incidence is known to be the angle between the incident ray and the normal.

The Angle of reflection is the angle between the reflected ray and the normal.

This normal ray is a ray that is perpendicular to the surface.

According to the question, if the beam of light is reflected off the surface and its angle of incidence is 30°, its angle of reflection will also be 30° i.e i=r = 30°

7 0

3 years ago

A wheel is used to turn a valve stem on a water valve. How much is the mechanical advantage when an effort of 80 lbs. is applied

Ann [662]

Answer:

Explanation:

From the question given above, the following data were obtained:

Effort (E) = 80 lbs

Load (L) = 320 lbs

Mechanical advantage (MA) =?

Mechanical advantage is simply defined as the ratio of load to effort. Mathematically, it is expressed as:

Mechanical advantage = Load / Effort

MA = L / E

With the above formula, we can obtain the mechanical advantage as illustrated below:

Effort (E) = 80 lbs

Load (L) = 320 lbs

Mechanical advantage (MA) =?

MA = L / E

MA = 320 / 80

MA = 4

Thus, the mechanical advantage is 4

3 0

2 years ago

two engines are turned on for 763 s at a moment when the velocity of the craft has x and y components of v0x = 6380 m/s and v0y

svet-max [94.6K]

Answer:

Explanation:

Given

initial velocity component of engines is

$v_0_x=6380 m/s$

$v_0_y=6770 m/s$

time period of engine running=763 s

Displacement in $x=4.50\times 10^6$

$y=7.27\times 10^6$

Using $s=ut+\frac{at^2}{2}$ in x and y direction

$x=v_0_x\times t+\frac{at^2}{2}$

$4.50\times 10^6=6380\times 763+\frac{a\times 763^2}{2}$

$4.50\times 10^6-4.86\times 10^6=\frac{a\times 763^2}{2}$

$a=-1.23 m/s^2$

In y direction

$y=v_0_y\times t+\frac{a't^2}{2}$

$7.27\times 10^6=6770\times 763+\frac{a\times 763^2}{2}$

$7.27\times 10^6-5.16\times 10^6=\frac{a\times 763^2}{2}$

$a=7.24 m/s^2$

x component $=-1.23 m/s^2$

y component $=7.24 m/s^2$

3 0

2 years ago

Read 2 more answers

Explain why Earth is not spherical in shape, but bulges at<br> theEquator?

Strike441 [17]

Explanation:

Every rotating body experiences centrifugal force. Due to this force the body tends to bulge out around it mid point and gets flattened at the poles. Same is applicable to Earth as well. Since the Earth is rotating at a very high speed, its equator gets bulged out due to centrifugal force. Because of this bulged equator, Earth's pole to pole diameter and equatorial diameter has difference of around 42.76 km. It is flatter on the poles. This also proves that Earth is not a perfect sphere.

8 0

2 years ago

Read 2 more answers

rosijanka [135]

Answer:

its deepend on where you stand but. most cases g = 10 m/s²

W = M X G

W = 13 kg x 10 m/s²

W = 130 N

Explanation:

option b is correct brainlist ke

3 0

2 years ago