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3 years ago

How many moles of each element are in one mole of Sr(HCO3)2?

Chemistry

2 answers:

Alla [95]3 years ago

7 0

Sr = 1 mol
H = C = 2 mol each
O = 6 mol

Alchen [17]3 years ago

6 0

Explanation:

Since it is given that the compound $Sr(HCO_{3})_{2}$ is one mole.

So, the elements present in it are strontium, hydrogen, carbon and oxygen.

Therefore, moles of elements present in $Sr(HCO_{3})_{2}$ are as follows.

Number of strontium atom is 1.

Number of hydrogen atoms are 2.

Number of carbon atoms are 2.

Number of oxygen atoms are $3 \times 2$ = 6.

Thus, we can conclude that there is 1 mole of Sr element, 2 mole of H element, 2 mole of carbon atom, and 6 moles of oxygen atom.

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grigory [225]

Answer:

B. It would lead to an increase of global temperatures.

Explanation:

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1 year ago

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When the particles of two objects have the same average kinetic energy, what do we know about those objects?

Dmitriy789 [7]

That they both will be the same average kinetic energy

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3 years ago

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Inga [223]

Answer:

Explanation:

In order for glucose to be produced inside the mixture, photosynthesis has to take place. The photosynthetic process requires a series of steps within an organelle called the chloroplast. The chloroplast contains the chlorophyll and other enzymes that are necessary for photosynthesis.

Once the chlorophyll is isolated, it becomes separated from the enzymes necessary for the completion of photosynthesis, and the process is truncated. When light is shined on the mixture, the majority would instead be lost as heat while some cause the chlorophyll molecules to glow.

7 0

2 years ago

What is the total amount of heat released when 94.0 g water at 80.0 °C cools to form ice at −30.0 °C?

Wewaii [24]

Answer:

The total amount of heat released is 68.7 kJ

Explanation:

Given that:

mass of water = 94.0 g

moles of water = 94 / 18.02 = 5.216

80⁰C ------> 0⁰C --------> -30⁰C

Q1 = m Cp dT

= 94 x 4.184 x (0 - 80)

= -31463.68 J

= -31.43 kJ

Q2 = 6.01 x 10^3 x 5.216

= - 31348.16 J

= -31.35 kJ

Q3 = - 94 x 2.09 x 30

= - 5893.8 J

= -5.894 kJ

Total heat = Q1 + Q2 + Q3 = -31.43 kJ + (-31.35 kJ ) + (-5.894 kJ ) = -68.7 kJ

Total heat released = -68.7 kJ

Note that the "negative sign" simply indicates heat released, therefore no need to put it in the answer.

6 0

2 years ago

Specific Heat Material Copper Aluminum Gold Pyrex Specific Heat (J/g °C) 0.385 0.902 0.129 0.75 Material Water Ice Olive Oil Air

zimovet [89]

Explanation:

It is known that the amount of heat necessary to raise the temperature of 1 gram of a substance by $1^{o}C$ is known as specific heat.

Since, q = $mC \Delta T$

So, larger is the specific heat of a substance less will be the change in its temperature.

Therefore, olive oil has less specific heat as compared to water. This means that olive oil would get hotter.

Similarly, the specific heat of gold is lesser than the given materials or metals. Hence, gold will requires less heat to rise its temperature.

As a result, water present in gold will heat readily.

As the relation between heat and specific heat is as follows.

q = $mC \Delta T$

Therefore, calculate the amount of heat required by the water as follows.

q = $mC \Delta T$

= $100 g \times 4.18 J/g^{o}C \times (100 - 20)^{o}C$

= 33440 J

or, = 33.44 kJ (as 1 kJ = 1000 J)

Thus, 33.44 kJ heat would it take to raise the temperature of 100.0 g of water from $20.0^{o}C$ to $100.0^{o}C$ .

3 0

3 years ago