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k0ka [10]
3 years ago
7

What is the 10% rule? What is its significance? Why is energy lost?

Chemistry
1 answer:
TEA [102]3 years ago
4 0
The 10% rule means that approximately there will be only 10% energy transferred from a trophic level into another. That was because the consumer on the upper level will use the energy before it was consumed. About 90% of the energy used so only 10% remain will be transferred.
Example: an antler eating grass with a total 100 calories. Then the antler is moving and growing, using 90 calories. Then a lion eats the antler, but the energy remains is only 10 calorie because 90 calories are already used.
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Considering the combustion reaction of propane again, what mass of propane (C3Hg) is necessary to react with 4.53 g of oxygen? C
zimovet [89]

Answer:

1.25 g C3H8

Explanation:

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7 0
2 years ago
A 1.1000 gram carbonate sample chosen from Li2CO3, K2CO3, Na2CO3 and CaCO3 was reacted with H2SO4 and was found to lose 0.3497 g
Stels [109]

<u>Answer:</u>

<u>For 1:</u> The percentage composition of CO_2 in unknown carbonate sample is 31.79 %

<u>For 2:</u> The unknown carbonate sample is potassium carbonate.

<u>Explanation:</u>

To calculate the percentage composition of carbon dioxide in sample, we use the equation:

\%\text{ composition of }CO_2=\frac{\text{Mass of }CO_2}{\text{Mass of sample}}\times 100     .....(1)

  • <u>For 1:</u>

Mass of sample = 1.1000 g

Mass of carbon dioxide = 0.3497 g

Putting values in equation 1, we get:

\%\text{ composition of }CO_2=\frac{0.3497g}{1.1000g}\times 100=31.79\%

Hence, the percentage composition of CO_2 in unknown carbonate sample is 31.79 %

  • <u>For 2:</u>

We are given:

Mass of carbon dioxide = [1\times 12.01)+(2\times 16.00)]=44.01g

  • <u>For lithium carbonate:</u>

Mass of lithium carbonate= 73.892 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

\%\text{ composition of }CO_2=\frac{44.01g}{73.892g}\times 100=59.55\%

The percent composition of carbon dioxide in lithium carbonate is 59.55 %

  • <u>For potassium carbonate:</u>

Mass of potassium carbonate= 138.21 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

\%\text{ composition of }CO_2=\frac{44.01g}{138.21g}\times 100=31.84\%

The percent composition of carbon dioxide in potassium carbonate is 31.84 %

  • <u>For sodium carbonate:</u>

Mass of sodium carbonate= 105.99 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

\%\text{ composition of }CO_2=\frac{44.01g}{105.99g}\times 100=41.52\%

The percent composition of carbon dioxide in sodium carbonate is 41.52 %

  • <u>For calcium carbonate:</u>

Mass of calcium carbonate = 100.09 g

Mass of carbon dioxide = 44.01 g

Putting values in equation 1, we get:

\%\text{ composition of }CO_2=\frac{44.01g}{100.09g}\times 100=43.97\%

The percent composition of carbon dioxide in calcium carbonate is 43.97 %

As, the percent composition of carbon dioxide in the unknown sample matches the percent composition of carbon dioxide in potassium carbonate.

Hence, the unknown carbonate sample is potassium carbonate.

7 0
3 years ago
If we dissolve 27 g of salt in 249 g of water, what is the mass of the resulting solution?
zavuch27 [327]

Answer:

276g

Explanation:you are adding salt to water the mass is not destroyed so you just add the numbers hope this helps god bless

7 0
3 years ago
How many moles are in 325mL of 1.25M (NH4)2SO4
mote1985 [20]

Answer:

n_{solute}=0.406mol(NH_4)_2SO_4

Explanation:

Hello,

In this case, since the molarity is defined as the ratio of the moles of the solute to the volume of the solution in liters:

M=\frac{n_{solute}}{V_{solution}}

For the given volume and molarity, we solve for the moles of ammonium sulfate (solute) as shown below:

n_{solute}=M*V_{solution}=1.25\frac{mol}{L}*325mL*\frac{1L}{1000mL}  \\\\n_{solute}=0.406mol(NH_4)_2SO_4

Best regards.

4 0
3 years ago
Over time the Mexican-Free Tailed bat has evolved to be able to echolocate in the dark to find prey. Bats are able to see, but d
Law Incorporation [45]

Answer:

Light

Explanation:

1 They were not albe to see at night because it  was dark so the lack of light caused them to use echolocation.

Hope this helps

4 0
3 years ago
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