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Lady bird [3.3K]

3 years ago

11

Are these a function?

2 answers:

Molodets [167]3 years ago

8 0

Answer:

yes........these all are....

AVprozaik [17]3 years ago

3 0

Not 10 because -2 is used twice (x-value)

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Simplify -1-5 + 21.

BlackZzzverrR [31]

Answer:

15

Step-by-step explanation:

-1-5=-6

21-6=15

6 0

3 years ago

A restaurant offers three types of meats: chicken, beef,

sp2606 [1]

Answer:

200

Step-by-step explanation:

If the waiters surveyed 50 customers and half of the customer's favorite meat was chicken, then if 400 pieces of meat were ordered 200 pieces should be chicken.

If $\frac{50}{chicken}$ = $\frac{50}{25}$ = $\frac{1}{2}$ , then $\frac{400}{chicken}$ = $\frac{400}{2}$ = $2$

I hope that makes sense :)

7 0

3 years ago

Which number is a composite number 7 11 31 or 36 show your work.

Crank

36 because the rest are prime #'8

4 0

3 years ago

Read 2 more answers

For the vectors u and v with magnitudes u = 88 and v = 99, find the angle θ between u and v which makes u and v = 77.

WARRIOR [948]

Answer:

<h2>89.5°</h2>

Step-by-step explanation:

Using the vector formula $u.v = |u||v|cos\theta$

|u| = magnitude of vector u

|v| = magnitude of vector v

u.v is the dot product of vector u and v

Given |u| = 88, |v| = 99 and u.v = 77, to get $\theta$ we will substitute the given values into the equation above;

$77 = 88*99cos\theta\\cos\theta = \frac{77}{88*99} \\cos\theta = \frac{77}{8712} \\cos\theta = 0.008838\\\theta = cos^{-1} 0.008838\\\theta = 89.5^{0}$

4 0

3 years ago

What is the correct first step to solve this system of equations by elimination?

storchak [24]

$\bold{\huge{\pink{\underline{ Solution }}}}$

$\bold{\underline{ Given }}$

<u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

$\bold{\underline{ To \: Find }}$

<u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

$\bold{\underline{ Let's \: Begin }}$

$\sf{ 2x - 3y = -6 ...eq(1)}$

$\sf{ x + 3y = 12 ...eq(2)}$

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

$\sf{ 2( x + 3y = 12 )}$

$\sf{ 2x + 6y = 24 }$

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

$\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}$

$\sf{ 2x + 6y - 2x + 3y = 24 + 6 }$

$\sf{ 9y = 30 }$

$\sf{ y = 30/9}$

$\sf{\red{ y = 10/3}}$

<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>

$\sf{ 2x - 3(10/3) = -6 }$

$\sf{ 2x - 10 = -6 }$

$\sf{ 2x = -6 + 10}$

$\sf{ x = 4/2}$

$\sf{\red{ x = 2}}$

Hence, The value of x and y is 2 and 10/3

6 0

3 years ago