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ddd [48]
3 years ago
15

Question 3 0

Chemistry
1 answer:
Tanya [424]3 years ago
5 0

Answer:

Option D. KBr < KCl < NaCl

Explanation:

We'll begin by calculating the number of mole of each sample.

This can be obtained as follow:

For NaCl:

Mass = 1 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mole of NaCl =?

Mole = mass /Molar mass

Mole of NaCl = 1/58.5

Mole of NaCl = 0.0171 mole

For Kbr:

Mass = 1 g

Molar mass of KBr = 39 + 80 = 119 g/mol

Mole of KBr =?

Mole = mass /Molar mass

Mole of KBr = 1/119

Mole of KBr = 0.0084 mole

For KCl:

Mass = 1 g

Molar mass of KCl = 39 + 35.5 = 74.5 g/mol

Mole of KCl =?

Mole = mass /Molar mass

Mole of KCl = 1/74.5

Mole of KCl = 0.0134 mole

Summary

Sample >>>>>>>> Number of mole

NaCl >>>>>>>>>> 0.0171

KBr >>>>>>>>>>> 0.0084

KCl >>>>>>>>>>> 0.0134

Arranging the number of mole of the sampl in increasing order, we have:

KBr < KCl < NaCl

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Answer:

Electrons

Explanation:

According to the Valence Shell Electron Pair Repulsion Theory (VSEPR), the geometry of a molecule depends on the number of electron pairs (regions of electron density) on the central atom of the molecule. Electron pairs on the valence shell of the molecule tend to position themselves as far apart in space as possible to minimize repulsion between them. Hence, the orientation of these electron pairs is the ultimate determinant of the observed geometry of a molecule.

Lone pairs of electrons cause more repulsion than bond pairs of electrons on the central atom of a molecule. Hence when the central atom of a molecule contains lone pairs of electrons, the molecular geometry is usually distorted from the expected geometry on the basis of VSEPR theory.

Hence, electrons are the subatomic particles which are responsible for any change in the observed molecular geometry of a molecule.

6 0
3 years ago
Which statement below best describes the relationship of the reaction below?
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For every two AB produced, the reaction requires three A
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What do the noble gases have in common with the halogens? Both noble gases and halogens are
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2 years ago
If the mass of 293nv is 293.10 amu and that of 295nv is 295.45 amu , what is the atomic weight of nv?
ycow [4]

Answer;

294.13 amu

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3 0
3 years ago
An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci
lapo4ka [179]

Answer:

<u>Optical purity = 76.9231 %</u>

<u>Specific rotation of mixture = - 97.6923 °</u>

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = \frac {Excess}{Total\ Concentration}\times 100 = \frac {11.5-1.5}{11.5+1.5}\times 100 = 76.9231 %

<u>Optical purity = 76.9231 %</u>

Also,

Optical purity = \frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100

Optical rotation of pure enantiomer = −127 °

76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100

<u>Specific rotation of mixture = - 97.6923 °</u>

6 0
3 years ago
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