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solong [7]
3 years ago
5

Solve 64÷4 using an area model

Mathematics
1 answer:
bekas [8.4K]3 years ago
5 0
The ANWSER is 16 I don't think I can show you a area model try your best you can make 64 squares the get and put them into groups of 4 if that helps and there should be 16 groups
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It took kelly 3 5/7 hours to fly from city A to City B, then it took her another 7 3/5 hours to fly from city B to City C. Kelly
saul85 [17]
Kelly flew a total of 11 11/35 hours
4 0
4 years ago
1. Use the formula d=rt. FInd the rate when d=13 mi and t=3 h.
lakkis [162]
1.
d = rt
13 = r*3
r = 13/3

2.
v = r + at
a = (v-r)/t
3 0
4 years ago
Which could be the side lengths of a right triangle?
Vsevolod [243]

Answer:

B

Step-by-step explanation:

90+45+45=180

All triangles equal 180.

Its B because if one angle is 90° then the other angles will equal each other. It cant be 60° and 30° because they dont equal, so your final answer is B.

Hope this Helps!!! :)

5 0
3 years ago
Read 2 more answers
Please help with these few questions
Tasya [4]

Answer:

Please help with these few questions

6. Use the picture to find the following angle measures.

9. Write a two -column proof for the following :

Given: angle1 and angle2 form a linear pair and m angle1= 2(m angle2)

Prove : m angle2 =60

10. Write a two-column proof for the following:

Given : AB = CD , AB = 4x + 1, and CD = 6x - 13

Prove: x = 7

Step-by-step explanation:

Please help with these few questions

6. Use the picture to find the following angle measures.

9. Write a two -column proof for the following :

Given: angle1 and angle2 form a linear pair and m angle1= 2(m angle2)

Prove : m angle2 =60

10. Write a two-column proof for the following:

Given : AB = CD , AB = 4x + 1, and CD = 6x - 13

Prove: x = 7

5 0
3 years ago
Given: ΔABC is a right triangle. Prove: a2 + b2 = c2 The following two-column proof with missing justifications proves the Pytha
Anestetic [448]

Answer:

Transitive property of equality is not a justification for the proof.

Step-by-step explanation:

We draw a right angle ΔACB. CD is perpendicular to AB.

Let AC = a , BC = b , AB = c and CD = h

Now in ΔABC and ΔACD

∠C = ∠D and ∠A = ∠A

from AA similarity postulate

ΔABC  similar to ΔACD.

Hence,

           \frac{c}{a} = \frac{a}{x}

           a^{2} = c × x ·····················(1)

Now in ΔABC and ΔCBD

∠C = ∠D and ∠B = ∠B

from AA similarity postulates

ΔABC similar to ΔCBD

Hence,

           \frac{c}{b} = \frac{b}{y}

           b^{2} = c × y······················(2)

Add equation (1) and (2)

      a^{2} + b^{2} = cx + cy

      a^{2} + b^{2} = c(x+y)

      a^{2} + b^{2} = c^{2}               [because x+y=c]

Transitive property is not useful for this proof.

5 0
3 years ago
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