Answer:
the interaction in the protein is greater than the surface with water
\frac{F_i}{F_s} = \frac{\epsilon_s}{ \epsilon_i} \ > 1
Explanation:
The electric force for a charge is
F =
In the exercise indicate that the charge is q and the distance r is maintained, the test charge is another
therefore if we use the index i for the dielectric constant () in the protein
the electric force in water with dielectric constant ()
if we look for the relationship between these forces
therefore the interaction in the protein is greater than the surface with water