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Sergeeva-Olga [200]
3 years ago
12

Work and energy both have the unit?

Physics
1 answer:
sveta [45]3 years ago
6 0
The both have the unit (J) for Jules
 
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To a good approximate, the only external force that does work on a cyclist moving on level ground is the force of air resistance
mart [117]

Answer:

a. 120 W

b. 28.8 N

Explanation:

To a good approximate, the only external force that does work on a cyclist moving on level ground is the force of air resistance. Suppose a cyclist is traveling at 15 km/h on level ground. Assume he is using 480 W of metabolic power.

a. Estimate the amount of power he uses for forward motion.

b. How much force must he exert to overcome the force of air resistance?

(a) He is 25% efficient, therefore the cyclist will be expending 25% of his power to drive the bicycle forward

Power = efficiency X metabolic power

= 0.25 X 480

= 120 W

(b)

power if force times the velocity

P = Fv

convert  15 km/h to m/s

v = 15 kmph = 4.166 m/s

F = P/v

= 120/4.166

= 28.8 N

definition of terms

power is the rate at which work is done

force is that which changes a body's state of rest or uniform motion in a straight line

velocity is the change in displacement per unit time.

3 0
3 years ago
for much of the year this desert is hot dry and windy.What type of plant would you most expect to survive in this climate
abruzzese [7]
I think the answer is cactus
7 0
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What could you include to give a sense of scale in a photograph of a mountain?
Shalnov [3]
Lighting gives a sense of scale (The sky)
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Below is a diagram of the orbits of the inner planets examine the diagram and answer questions three and four 
drek231 [11]

Answer:

C is the answer

Explanation:

Earth is the third planet from the sun

you are cheating on your test, I know

3 0
3 years ago
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A box of mass 12 kg is at rest on a flat floor. The coefficient of static friction between the box and floor is 0.42. What is th
Oxana [17]
The maximum static force that can be applied is equal to the normal force*the frictional force. the normal force on the box is equal to mg since the floor is flat using 9.81m/s^2 for gravity 12kg*9.81m/s^2 = 118N multiplying the normal force by the frictional force you get a 118*.42= 49.6N so overcome the force of static friction on the box a minimum of 49.6N would need to be applied.
5 0
3 years ago
Read 2 more answers
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