Work and energy both have the unit?

defon

Answer:

b,c

Explanation:

Velocity refers to the rate of change of position with respect to time and acceleration refers to the rate of change of velocity with respect to time. Both velocity and acceleration are vector quantities

While the line of children is rotating, the player at the front of the line has the smallest linear velocity and all the children have the same angular acceleration.

7 0

3 years ago

The astronomical unit (AU) is defined as the mean center-to-center distance from Earth to the Sun, namely 1.496x10^(11) m. The p

Rudiy27

Answer:

a) How many parsecs are there in one astronomical unit?

$4.85x10^{-6}pc$

(b) How many meters are in a parsec?

$3.081x10^{16}m$

(c) How many meters in a light-year?

$9.46x10^{15}m$

(d) How many astronomical units in a light-year?

$63325AU$

(e) How many light-years in a parsec?

3.26ly

Explanation:

The parallax angle can be used to find out the distance using triangulation. Making a triangle between the nearby star, the Sun and the Earth, knowing that the distance between the Earth and the Sun ( $1.496x10^{11} m$ ) is defined as 1 astronomical unit:

$\tan{p} = \frac{1AU}{d}$

Where d is the distance to the star.

Since p is small it can be represent as:

$p(rad) = \frac{1AU}{d}$ (1)

Where p(rad) is the value of in radians

However, it is better to express small angles in arcseconds

$p('') = p(rad)\frac{180^\circ}{\pi rad}.\frac{60'}{1^\circ}.\frac{60''}{1'}$

$p('') = 2.06x10^5 p(rad)$

$p(rad) = \frac{p('')}{2.06x10^5}$ (2)

Then, equation 2 can be replace in equation 1:

$\frac{p('')}{2.06x10^5} = \frac{1AU}{d}$

$\frac{d}{1AU} = \frac{2.06x10^5}{p('')}$ (3)

From equation 3 it can be see that $1pc = 2.06x10^5 AU$

a) How many parsecs are there in one astronomical unit?

$1AU . \frac{1pc}{2.06x10^5AU}$ ⇒ $4.85x10^{-6}pc$

(b) How many meters are in a parsec?

$2.06x10^{5}AU . \frac{1.496x10^{11}m}{1AU}$ ⇒ $3.081x10^{16}m$

(c) How many meters in a light-year?

To determine the number of meters in a light-year it is necessary to use the next equation:

$x = c.t$

Where c is the speed of light ( $c = 3x10^{8}m/s$ ) and x is the distance that light travels in 1 year.

In 1 year they are 31536000 seconds

$x = (3x10^{8}m/s)(31536000s)$

$x = 9.46x10^{15}m$

(d) How many astronomical units in a light-year?

$9.46x10^{15}m . \frac{1AU}{1.496x10^{11}m}$ ⇒ $63325AU$

(e) How many light-years in a parsec?

$2.06x10^{5}AU . \frac{1ly}{63235AU}$ ⇒ $3.26ly$

5 0

3 years ago

What is one main difference between animal cells and plant cells?

vekshin1

Answer:

No cell wall

Explanation:

7 0

2 years ago

During anomalous expansion of water ,heat transfer is limited to conduction and radiation only ,explain.

aalyn [17]

Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density

<h3>What is anomalous expansion of water?</h3>

Anomalous expansion of water is a property of water in which water expands instead of contracting.

Anomalous expansion of water makes water less dense.
The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.

Learn more about properties of water:

brainly.com/question/18681949

4 0

1 year ago

What is the kinetic energy of an object with a mass of 50kg and is and it is traveling at a rate of 60m/s.

liq [111]

Answer:

90,000 J

Explanation:

Kinetic energy can be found using the following formula.

$KE=\frac{1}{2}mv^2$

where m is the mass in kilograms and v is the velocity in m/s.

We know the object has a mass of 50 kilograms. We also know it is a traveling at a rate of 60 m/s. Velocity is the speed of something, so the velocity of the object is 60 m/s.

m=50

v=60

Substitute these values into the formula.

$KE=\frac{1}{2}*50*60^2$