The wavelength of the third line in the Lyman series, and identify the type of EM radiation
In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.
1 / lambda = R(h)* ( 
- 
)
= 109678 ( 
- 
)
= 109678 (8/9)
Lambda = 9 / (109678 * 8 )
= 102.6 * 
m = 102.6 nm
To learn more about Lyman series here
brainly.com/question/5762197
#SPJ4
Answer:
<em>a) 28877 AU</em>
<em>b) 1.795 sec</em>
<em></em>
Explanation:
Time it took the radio signal to reach earth = 4 hours = 4 x 3600 = 14400 s
speed of radio signal = speed of vacuum speed of light = 3 x 10^8 m/s
Distance traveled by this signal = speed x time
distance = 3 x 10^8 x 14400 = 4.32 x 10^12 m
One Astronomic unit AU is the distance between the Earth and the sun and it is approximately equal to 1.496 x 10^8 m
The distance traveled by the signal in AU = (4.32 x 10^12)/(1.496 x 10^8) = <em>28877 AU</em>
b) The minimum separation between Earth and Mars = 0.36 AU
This distance = 0.36 x 1.496 x 10^8 = 538560000 m
Time that will be taken for a radio signal to travel this distance = distance/speed
==> 538560000/(3 x 10^8) = <em>1.795 sec</em>
B. Barometer is used to measure atmospheric pressure.
Answer:
B) 1218
Explanation:
N = Total number of turns in the solenoid
L = length of the solenoid = 34.00 cm = 0.34 m
B = magnetic field at the center of the solenoid = 9 mT = 9 x 10⁻³ T
i = current carried by the solenoid = 2.000 A
Magnetic field at the center of the solenoid is given as
N = 1218
The electrical power or rate at which internal energy is produced in the copper wires is 435.6 W.
<h3>What is the internal rate at which internal energy is produced in the copper wires?</h3>
The internal energy produced in the copper wires is energy due to the resistance in the wire and is converted to heat energy.
The rate at which it is produced is electrical power.
Therefore, the rate at which internal energy produced in the copper wires is given as follows:
Power = I²R
R = l * 0.108 Ω/300m
Power = 110² * (2 * 50 * 0.108 Ω/300m)
Power = 435.6 W
In conclusion, electrical power is lost as heat in the wires.
Learn more electrical power at: brainly.com/question/25781540
#SPJ4
