Answer:
Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.
Explanation:
Answer:
Im answering for free points sry
Explanation:
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Answer:
The linear speed of scratch is 45.55 cm/dec
Explanation:
The scratch located from the center at radial distance = 14.5 cm.
Each minute the skip of scratch when disco record played = 30 times
Since, the scratch on the disc start revolving when disc is played and in one minute the scratch revolve 30 times. Therefore, the revolution = 30 RPM
Below is the calculation of linear speed of the scratch.






<span>La segunda ley de Newton se conoce como la ley del movimiento de las partículas. <span>Dice que si sobre un cuerpo de masa en una sola fuerza Féliz que recibe una descarga de tal que F = ma.
</span></span>Y la primera <span>establece que un objeto permanecerá en reposo o con movimiento unifome rectilíneo al menos que sobre él actúe una fuerza externa.
Espero q te sirva :)</span>
Answer: The correct answer is B. trust me, I just took that test. :)