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IceJOKER [234]
3 years ago
6

What is the periodic table a list of

Chemistry
1 answer:
barxatty [35]3 years ago
5 0

Answer:

i think c should be ur answer

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Answer? giving brainlyest
salantis [7]

Answer:

r=3

Explanation:

6 0
3 years ago
How many moles of gas occupy 98 l at a pressure of 2.8 atmosphere and a temperature of 292
lara [203]

Answer:

n = 11.45 mol

Explanation:

Given data:

Number of moles = ?

Volume of gas = 98 L

Pressure = 2.8 atm

temperature = 292 K

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

2.8 atm × 98 L = n × 0.0821 atm.L/ mol.K   × 292 K

274.4 atm.L = n ×  23.97atm.L/ mol

n = 274.4 atm.L /23.97atm.L/ mol

n = 11.45 mol

8 0
3 years ago
Aluminum bromide and chlorine gas react to<br> form aluminum chloride and bromine gas.
Margarita [4]

Answer:

ok

Explanation:

4 0
3 years ago
How much energy is required to raise the temperature of 3kg of iron from 20 degrees Celsius to 25 degrees Celsius
Yuri [45]

Answer:

6750 J

Explanation:

The specific heat capacity of iron is 450 J/kg/K

Quantity of heat = mcθ; where m is the mass and c is the specific heat capacity and θ is the temperature change.

Therefore;

m = 3 kg, c = 450 J/kg/K and θ = 5°C

Quantity of heat = 3 × 450 × 5

                           <u>= 6150 Joules</u>

5 0
3 years ago
Which of the samples described below contains the FEWEST atoms? No calculation is needed to answer this question.
Monica [59]

Hello!

To do this, use the molar mass. This is how much a mole of an atom weighs. A mole is 6.02214076×10²³ atoms.

Molar masses of:

Se: 78.96 g/mol

Cu: 63.546 g/mol

Ba: 137.327 g/mol

Now, the element with the highest molar mass will have the fewest atoms. This is because the element weighs more, so therefore for the same amount of mass, there will be less of the element needed to reach that mass.

Therefore, 10g of Ba would have the fewest number of atoms.

Hope this helps!

6 0
4 years ago
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