Answer:
1.a=2
2. C x=2 and x=-3
Step-by-step explanation:
The standard form for the quadratic function is
ax^2 +bx+c
so we need to rewrite the function to be in this form
2x^2 -10 = 7x
Subtract 7x from each side
2x^2 -7x-10 = 7x-7x
2x^2 -7x-10 = 0
a =2, b= -7 c=-10
2. The quadratic formula is
-b ± sqrt(b^2 -4ac)
----------------------------
2a
2x^2 + 2x=12
Lest get the equation in proper form
2x^2 + 2x-12 = 12-12
2x^2 +2x-12 =0
a=2 b=2 c=-12
Lets substitute what we know
-2 ± sqrt(2^2 -4(2)(-12))
----------------------------
2(2)
-2 ± sqrt(4+96)
----------------------------
2(2)
-2 ± sqrt(100)
----------------------------
4
-2 ± 10
----------------------------
4
-2 + 10 -2-10
----------- and --------------
4 4
8/4 and -12/4
2 and -3
79.55449 your welcome this is totally wrong lol sos
Answer: (1,0)
Step-by-step explanation:
Answer:
-3+x=x+4
Step-by-step explanation:
Pls Mark Brainliest
Answer:
x = -2 and y = 3
{y = -3 x - 3, y = (3 x)/4 + 9/2} = x = -2 and y = 3
Step-by-step explanation:
Solve the following system:
{6 x + 2 y = -6
3 x - 4 y = -18
Express the system in matrix form:
(6 | 2
3 | -4)(x
y) = (-6
-18)
Solve the system with Cramer's rule:
x = -6 | 2
-18 | -4/6 | 2
3 | -4 and y = 6 | -6
3 | -18/6 | 2
3 | -4
Evaluate the determinant 6 | 2
3 | -4 = -30:
x = -6 | 2
-18 | -4/(-30) and y = 6 | -6
3 | -18/(-30)
Simplify -6 | 2
-18 | -4/(-30):
x = -1/30 -6 | 2
-18 | -4 and y = 6 | -6
3 | -18/(-30)
Simplify 6 | -6
3 | -18/(-30):
x = -(-6 | 2
-18 | -4)/30 and y = -1/30 6 | -6
3 | -18
Evaluate the determinant -6 | 2
-18 | -4 = 60:
x = (-1)/30×60 and y = -(6 | -6
3 | -18)/30
(-1)/30×60 = -2:
x = -2 and y = -(6 | -6
3 | -18)/30
Evaluate the determinant 6 | -6
3 | -18 = -90:
x = -2 and y = (-1)/30×-90
(-1)/30 (-90) = 3:
Answer: x = -2 and y = 3
___________________________________________
Solve the following system:
{y = -3 x - 3
y = (3 x)/4 + 9/2
Express the system in standard form:
{3 x + y = -3
-(3 x)/4 + y = 9/2
Express the system in matrix form:
(3 | 1
-3/4 | 1)(x
y) = (-3
9/2)
Write the system in augmented matrix form and use Gaussian elimination:
(3 | 1 | -3
-3/4 | 1 | 9/2)
Add 1/4 × (row 1) to row 2:
(3 | 1 | -3
0 | 5/4 | 15/4)
Multiply row 2 by 4/5:
(3 | 1 | -3
0 | 1 | 3)
Subtract row 2 from row 1:
(3 | 0 | -6
0 | 1 | 3)
Divide row 1 by 3:
(1 | 0 | -2
0 | 1 | 3)
Collect results:
Answer: {x = -2
, y = 3
