(7,-1)
comment if u want me to explain the answer
Answer:
Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is
13x - 4y = 84.
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( 4 ,-8)
point B( x₂ , y₂) ≡ (8 , 5)
To Find:
Equation of Line AB =?
Solution:
Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula

Substituting the given values in a above equation we get

Therefore the equation of the line through ( 4 , -8 ) and ( 8 , 5 ) is
13x - 4y = 84.
Step-by-step explanation:
7x + 8y = -12
8y=-12-7x
y=

Answer:
So interval notation is with ( and [ where ( is exclusive and [ is inclusive.
Like (1,2) is between 1 and 2 exclusive. [1,2] is between 1 and 2 inclusive. (1,2] is between 1 and 2, 1 exclusive 2 inclusive.
at the point (6,0) you see that the graph goes from above 0 to below 0 (from positive to negative)
The values are positive when x is less than 6 and negative when x is greater than 6.
so the positive interval is
(-infinity, 6)
and with inifinity you always use exclusive
It's that because everything from all the way to the left (-infinity) to 6, is above the x-axis, which means it's positive
using this logic can you do the negative interval?
Matrix A was expressed in the form of a 2x2
i'm not sure if this helps or not but here you go