Question

A circuit contains two light bulbs connected in parallel. What would happen to the brightness of each light bulb if two more light bulbs were added in parallel to the first ones? The brightness of each bulb would decrease because the total resistance of the circuit would decrease. The brightness of each bulb would increase because the total resistance of the circuit would increase. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease. The brightness of each bulb would remain the same even though the total resistance of the circuit would increase.

Answer 1

Answer:

The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Explanation:

Brightness of the bulb is given as

$P= \frac{V^2}{R}$

since all bulbs are connected in parallel so here voltage across each bulb will remain same and resistance of each bulb is "R"

So here power across each bulb will remain the same always.

So there will be no effect on the power or brightness of bulb.

Now we also know that equivalent resistance is given as

$\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}............$

$R_{eq} = \frac{R}{n}$

so here equivalent resistance will decrease on adding more resistance in parallel.

so correct answer will be

The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Answer 2

Answer: C ON EDGE

Explanation: