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AleksAgata [21]
3 years ago
6

A circuit contains two light bulbs connected in parallel. What would happen to the brightness of each light bulb if two more lig

ht bulbs were added in parallel to the first ones? The brightness of each bulb would decrease because the total resistance of the circuit would decrease. The brightness of each bulb would increase because the total resistance of the circuit would increase. The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease. The brightness of each bulb would remain the same even though the total resistance of the circuit would increase.
Physics
2 answers:
DENIUS [597]3 years ago
6 0

Answer:

The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Explanation:

Brightness of the bulb is given as

P= \frac{V^2}{R}

since all bulbs are connected in parallel so here voltage across each bulb will remain same and resistance of each bulb is "R"

So here power across each bulb will remain the same always.

So there will be no effect on the power or brightness of bulb.

Now we also know that equivalent resistance is given as

\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}............

R_{eq} = \frac{R}{n}

so here equivalent resistance will decrease on adding more resistance in parallel.

so correct answer will be

The brightness of each bulb would remain the same even though the total resistance of the circuit would decrease.

Likurg_2 [28]3 years ago
4 0

Answer: C ON EDGE

Explanation:

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Answer:

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Explanation:

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Terminal Velocity of a body falling through a fluid as in a diver falling through air is given by

v = √(2mg/ρcA)

where m = mass of body falling through fluid = 80 kg

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c = coefficient of drag friction of diver falling through air, as obtained from literature = 0.7

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3 years ago
Which term describes a gap in the geologic record that occurs when sedimentary rocks cover an eroded surface?
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3 years ago
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3 0
3 years ago
A car enters a level, unbanked semi-circular hairpin turn of 100 m radius at a speed of 28 m/s. The coefficient of friction betw
meriva

Answer:

As  28m/s = 28m/s

Explanation:

r = the radius of the curve

m =  the mass of the car

μ = the coefficient of kinetic friction

N = normal reaction

When rounding the curve, the centripetal acceleration is

a = \frac{v^{2}}{r}

therefore

\mu mg = m \frac{v^{2}}{r} \\\\ \mu =  \frac{v^{2}}{rg}

v = \sqrt{\mu rg}

\mu = \sqrt{0.8 \times 100\times9.8} \\\\= 28m/s

As  28m/s = 28m/s

8 0
4 years ago
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butalik [34]

Answer:

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Explanation:

The speed of a wave can be defined as:

v = \nu \cdot \lambda (1)

Where v is the speed, \nu is the frequency and \lambda is the wavelength.

Equation 1 can be expressed in the following way for the case of an electromagnetic wave:

c = \nu \cdot \lambda (2)              

 

Where c is the speed of light.    

Therefore, \lamba\lambda can be isolated from equation 2 to get the wavelength of the photon.

\lambda = \frac{c}{\nu} (3)

\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}

\lambda = 1.5x10^{-6}m

Hence, the photon has a wavelength of 1.5x10^{-6}m        

<em>Summary:  </em>

Photons are the particles that constitutes light.

3 0
4 years ago
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