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3 years ago

7

You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that emerges from this polarizer

falls on a second ideal polarizer. The light that emerges from the second polarizer has intensity 15.0 W/m2. Find the intensity of the light that emerges from the first polarizer.

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer:

The intensity of light from the first polarizer is $I_1 = 26 W/m^2$

Explanation:

The intensity of the unpolarized light is $I_o = 52.0 \ W/m^2$

Generally the intensity of light that emerges from the first polarized light is

$I_1 = \frac{I_o}{2 }$

substituting values

$I_1 = \frac{52. 0}{2 }$

$I_1 = 26 W/m^2$

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