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3 years ago

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You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that emerges from this polarizer

falls on a second ideal polarizer. The light that emerges from the second polarizer has intensity 15.0 W/m2. Find the intensity of the light that emerges from the first polarizer.

1 answer:

kondor19780726 [428]3 years ago

5 0

Answer:

The intensity of light from the first polarizer is $I_1 = 26 W/m^2$

Explanation:

The intensity of the unpolarized light is $I_o = 52.0 \ W/m^2$

Generally the intensity of light that emerges from the first polarized light is

$I_1 = \frac{I_o}{2 }$

substituting values

$I_1 = \frac{52. 0}{2 }$

$I_1 = 26 W/m^2$

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Answer:

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Explanation:

let p1 be the initial momentum of the ball and p2 be the final momentum of the ball. let v1 be the initial velocity of the ball and v2 be the final velocity of the ball.

From Newton's second law of motion, we get that the avarage force acting on the ball is given by:

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= m(v2 - v1)/t

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= - 12209 N

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. Maria walked 1.5 miles south to her house in 0.5 hours. What is her speed in miles per hour?

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$v=\frac{d}{t}$

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Explanation:

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In Completely Inelastic objects stick with each other

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