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Lemur [1.5K]
3 years ago
15

What equation would you use to calculate the ideal mechanical advantage of a wheel and axle? This is Science not Physics

Physics
1 answer:
Lyrx [107]3 years ago
3 0
<span> you divide the radius of the </span>wheel<span> by the radius of the </span>axle<span>.</span>
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What is the centripetal force acting on a 1.5 kg mass moving in a circular path with a centripetal
zloy xaker [14]

The centripetal force acting on a 1.5 kg mass moving in a circular path is 27N

A centripetal force is a net force acting on an object in order to maintain the object's movement in a circular motion.

According  to Newton's first law, it states an object will continue to proceed its movement in a straight line unless acted upon by an external force.

The centripetal force is the external force at work here and  It's the net force that propels the object in a circular motion.

Using the formula for calculating centripetal force:

\mathbf{F_c = mass (m) \times acceleration (a)}

\mathbf{F_c = 1.5 \ kg \times18 \ m/s^2}

\mathbf{F_c = 27 \ N}

Learn more about centripetal force here:

brainly.com/question/11324711?referrer=searchResults

8 0
3 years ago
The velocity of a 150 kg cart changes from 6.0 m/s to 14.0 m/s. What is the magnitude of the impulse that acted on it?
tensa zangetsu [6.8K]
M = 150 kg.

Final velocity, v = 14 m/s

Initial Velocity, u = 6 m/s

Impulse = <span> m(v - u)</span>
 
             = 150*(14 - 6)
           
             =  150*8 = 1200 kgm/s  or 1200 Ns<span> </span>
3 0
3 years ago
I NEED HELP PLS ASAP IM LITERALLY CONFUSED??????????
Eduardwww [97]
C. It pulls them together
4 0
3 years ago
Read 2 more answers
Consider a conical pendulum with a bob of mass m = 80.0 kg on a string of length L = 10.0 m that makes an angle of 5.0 degrees w
SCORPION-xisa [38]

Answer:

0.8582 m/s^2

Explanation:

mass of the bob m = 80 kg

length of the string L= 10.0 m

angle made with the vertical θ= 5.0

let the force exerted by the string = T

from the FBD

T cosθ= mg

T cos 6°= 80×9.81

⇒T= \frac{70\times9.81}{cos5}

= 787.79 N

how horizontal component of tension T_h

T_h= Tsin\theta

=787.79 sin 5°= 68.66 N

Now, radial acceleration, a_c= \frac{T_h}{m}

= 68.66/80=  0.8582 m/s^2

8 0
4 years ago
Drawing Conclusions Suppose you take a short piece of wire that is not attached to anything and move it up and down in a magneti
Ulleksa [173]

Answer: No. Circuit should be closed.

Explanation:

A changing magnetic field induces emf in a circuit which is placed in it. This induced emf causes current to flow through it. This is given by Faraday's law which states that induced emf results due to rate of change of magnetic flux.

e = \frac{-d\phi}{dt}= -\frac {dB A} {dt}

Current flows only through a closed circuit. Thus, when a wire is moved up and down in a magnetic field, it will not induce emf because the wire does not form a loop. It is an open circuit.

4 0
4 years ago
Read 2 more answers
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