Answer:
The average current is 19.567 A
Solution:
As per the question:
Charge, Q = 
Time, t = 
Now,
We know that current is constituted by the rate of transfer of the charge per unit time. Thus we can write:
I =
(1)
Now, the charge that was transferred is 86 % of the original value.
Therefore,
We replace Q by 0.86Q in eqn (1):
I = 
To solve this problem it is necessary to apply the concepts related to the conservation of energy, through the balance between the work done and its respective transformation from the gravitational potential energy.
Mathematically the conservation of these two energies can be given through

Where,
W = Work
Final gravitational Potential energy
Initial gravitational Potential energy
When the spacecraft of mass m is on the surface of the earth then the energy possessed by it

Where
M = mass of earth
m = Mass of spacecraft
R = Radius of earth
Let the spacecraft is now in an orbit whose attitude is
then the energy possessed by the spacecraft is

Work needed to put it in orbit is the difference between the above two


Therefore the work required to launch a spacecraft from the surface of the Eart andplace it ina circularlow earth orbit is

The symbol "E3" represents the energy of electrons in the third energy level.
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The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get,
<span>d = [n*MW]/ Na*[a^3]
</span><span>d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3]
</span>d = 0.719 g/cm3
First find the time it takes to hit the sand t
using s=1/2 g t^2
t^2= 8/9.8= 0.82 seconds
This means the sand was s = 8 * 0.82 = 6.5m away
The horizontal speed stays constant at 8 m/s
The vertical speed =.82 * 9.8 = 8.0 m/s
As the two velocities are equal the angle must be 45 degrees to the horizontal