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rjkz [21]
4 years ago
5

35 POINTS!!! The measures of the angles in a quadrilateral are represented by x, 2x, 3x, and 3x. Write an equation that would al

low you to solve for the value of x. Solve for the value of x
Mathematics
1 answer:
Marina86 [1]4 years ago
6 0

Answer:

The value of x is 40.

Step-by-step explanation:

The measures of the angles in a quadrilateral are represented by x, 2x, 3x, and 3x.

According to the angle sum property of quadrilateral, the sum of interior angles of a quadrilateral is always 360 degree.

Since the measures of the angles in a quadrilateral are represented by x, 2x, 3x, and 3x, therefore

x+2x+3x+3x=360

This is the equation which is used to solve for the value of x.

9x=360

x=\frac{360}{9}

x=40

Therefore the value of x is 40.

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Find an equation for the plane that is tangent to the surface z equals ln (x plus y )at the point Upper P (1 comma 0 comma 0 ).
alexira [117]

Let f(x,y,z)=z-\ln(x+y). The gradient of f at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.

So the tangent plane has equation

\nabla f(1,0,0)\cdot(x-1,y,z)=0

Compute the gradient:

\nabla f(x,y,z)=\left(\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y},\dfrac{\partial f}{\partial z}\right)=\left(-\dfrac1{x+y},-\dfrac1{x+y},1\right)

Evaluate the gradient at the given point:

\nabla f(1,0,0)=(-1,-1,1)

Then the equation of the tangent plane is

(-1,-1,1)\cdot(x-1,y,z)=0\implies-(x-1)-y+z=0\implies\boxed{z=x+y-1}

7 0
4 years ago
Please answer correctly !!!!!!!!!! Will mark brainliest !!!!!!!!!!
tigry1 [53]

Answer:

y = (-1/6)x^2

Step-by-step explanation:

Original function and graph:  y = x^2

Reflection across the x-axis is y = -x^2

Vertical scaling by a factor of 1/6:    y = (-1/6)x^2

6 0
3 years ago
Which phrase correctly describes the location of –19 on the number line?
bezimeni [28]

Answer:

Step-by-step explanation:

I can't give you a direct answer, but i know something that might help

6 0
3 years ago
If
likoan [24]

It's easy to show that 7\tan(4x) is strictly increasing on x\in\left[0,\frac\pi8\right]. This means

M = \max \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/12} = 7\sqrt3

and

m = \min \left\{7\tan(4x) \mid \dfrac\pi{16} \le x \le \dfrac\pi{12}\right\} = 7\tan(4x) \bigg|_{x=\pi/16} = 7

Then the integral is bounded by

\displaystyle 7\left(\frac\pi{12} - \frac\pi{16}\right) \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le 7\sqrt3 \left(\frac\pi{12} - \frac\pi{16}\right)

\implies \displaystyle \boxed{\frac{7\pi}{48}} \le \int_{\pi/16}^{\pi/12} 7\tan(4x) \, dx \le \boxed{\frac{7\sqrt3\,\pi}{48}}

7 0
2 years ago
What is the sin, cos, and tan of -495 degrees, and -20π/3  ??
Diano4ka-milaya [45]
Sin-495 = 0.98
cos-495 = 0.19
tan-495 = 4.95

sin<span>-20π/3</span> = 0
cos<span>-20π/3</span> = 0.3
tan<span>-20<span>π/3</span></span> = 0





7 0
3 years ago
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