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2 years ago

BF3 + Li2SO3 ----> B2(SO3)3 + LiF What is the coefficient of lithium fluoride in the balanced chemical reaction?

Chemistry

2 answers:

pishuonlain [190]2 years ago

7 0

Ans) 6

The given equation is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

# atoms in Reactants # atoms in Products

B = 1 B = 2

F = 3 F = 1

Li = 2 Li = 1

S = 1 S = 3

O = 3 O = 9

In order to balance the unequal distribution of atoms, multiply BF3 by 2, Li2SO3 by 3 and LiF by 6 to get:

2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF

Coefficient of LiF = 6

egoroff_w [7]2 years ago

6 0

2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + <u>6LiF

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What is the osmotic pressure of a solution made from 22.3 g of methanol (MM = 32.04 g/mol) that was added to water to make 321 m

xxMikexx [17]

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Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

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$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (methanol) = 22.3 g

Volume of solution = 321 mL

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K$

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2 years ago