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3 years ago

BF3 + Li2SO3 ----> B2(SO3)3 + LiF What is the coefficient of lithium fluoride in the balanced chemical reaction?

Chemistry

2 answers:

pishuonlain [190]3 years ago

7 0

Ans) 6

The given equation is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

# atoms in Reactants # atoms in Products

B = 1 B = 2

F = 3 F = 1

Li = 2 Li = 1

S = 1 S = 3

O = 3 O = 9

In order to balance the unequal distribution of atoms, multiply BF3 by 2, Li2SO3 by 3 and LiF by 6 to get:

2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF

Coefficient of LiF = 6

egoroff_w [7]3 years ago

6 0

2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + 6LiF

:)

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Mass percentage → 0.074 %

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Aqueous solution of flouride → [F⁻] = 0.0390 M

It means that in 1L of solution, we have 0.0390 moles of F⁻

We need the mass of solution and the mass of 0.0390 moles of F⁻

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A compound in a copper ore has the following percentage composition by mass:

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2) convert each gram to moles using the molar masses given

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