Question

BF3 + Li2SO3 ----> B2(SO3)3 + LiF What is the coefficient of lithium fluoride in the balanced chemical reaction?

Answer 1

Ans) 6

The given equation is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

# atoms in Reactants                                    # atoms in Products

B = 1                                                                   B = 2

F = 3                                                                   F = 1

Li = 2                                                                  Li = 1

S = 1                                                                    S = 3

O = 3                                                                   O = 9

In order to balance the unequal distribution of atoms, multiply BF3 by 2,  Li2SO3 by 3 and LiF by 6 to get:

2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF

Coefficient of LiF = 6

Answer 2

2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + 6LiF

:)