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Alenkasestr [34]
3 years ago
14

BF3 + Li2SO3 ----> B2(SO3)3 + LiF What is the coefficient of lithium fluoride in the balanced chemical reaction?

Chemistry
2 answers:
pishuonlain [190]3 years ago
7 0

Ans) 6

The given equation is:

BF3 + Li2SO3 → B2(SO3)3 + LiF

# atoms in Reactants                                    # atoms in Products

B = 1                                                                   B = 2

F = 3                                                                   F = 1

Li = 2                                                                  Li = 1

S = 1                                                                    S = 3

O = 3                                                                   O = 9

In order to balance the unequal distribution of atoms, multiply BF3 by 2,  Li2SO3 by 3 and LiF by 6 to get:

2BF3 + 3Li2SO3 → B2(SO3)3 + 6LiF

Coefficient of LiF = 6

egoroff_w [7]3 years ago
6 0
2BF₃ + 3Li₂SO₃ ----> B₂(SO₃)₃ + <u>6LiF

</u>:)<u>

</u>
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Explanation:

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Use the table on the right to calculate each required quantity.
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Sodium (na), atomic number 11, has a tendency to lose an electron in the presence of chlorine. after losing the electron, na has
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Express the concentration of a 0.0390 M aqueous solution of fluoride, F − , in mass percentage and in parts per million (ppm). A
Vadim26 [7]

Answer:

Mass percentage → 0.074 %

[F⁻] = 741 ppm

Explanation:

Aqueous solution of flouride → [F⁻] = 0.0390 M

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Mass of solution can be determined by density:

1g/mL = Mass of solution / 1000 mL

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Ppm = mass of solute . 10⁶ / mass of solution (mg/kg)

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A compound in a copper ore has the following percentage composition by mass:
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2) convert each gram to moles using the molar masses given

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S-----> 0.875 / 0.293= 3

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Cu₃FeS₃
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