Question

The Atmospheric Pressure At This Altitude Is 461 MmHg. Assuming That The Atmosphere Is 18% Oxygen (by Volume), Calculate The Partial Pressure Of O2.

Answer 1

Answer:

The partial pressure of the oxygen is 82.98 mmHg.

Explanation:

From the given,

Atmospheric pressure = 461 mmHg

Atmospheric oxygen = 18%

Partial pressure of  oxygen =?

$Partial\,pressure\,of\,oxygen\,=\,Total\,pressure\timesVolume\,fraction$

$= \text{461\,mmHg} \times \frac{18}{100}\,=82.98\, \text{mmHg}$

Therefore, Partial pressure of oxygen is 82.98 mmHg.