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Oliga [24]
3 years ago
11

The Atmospheric Pressure At This Altitude Is 461 MmHg. Assuming That The Atmosphere Is 18% Oxygen (by Volume), Calculate The Par

tial Pressure Of O2.
Chemistry
1 answer:
Nadya [2.5K]3 years ago
5 0

Answer:

The partial pressure of the oxygen is 82.98 mmHg.

Explanation:

From the given,

Atmospheric pressure = 461 mmHg

Atmospheric oxygen = 18%

Partial pressure of  oxygen =?

Partial\,pressure\,of\,oxygen\,=\,Total\,pressure\timesVolume\,fraction

=$\text{461\,mmHg}$\times \frac{18}{100}\,=82.98\,$\text{mmHg}$

Therefore, Partial pressure of oxygen is 82.98 mmHg.

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      1           :          3         :            2      :         3

   13.3       <---     40    ------> 26.6      --->     40    ( mol)

n = m/M

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p/s : i hope that this will help  ( cause i'm not really good at english :}}} )

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