The compound is basic in nature but the concentration substance is corrosive.
<h3>What is NaOH?</h3>
Sodium hydroxide is a compound that is formed from sodium and hydrogen as well as oxygen The compound is basic in nature but the concentration substance is corrosive.
a) The acute health effect of exposure to NaOH is skin burn while the chronic effect of exposure is damage to the lungs.
b) The first aid for the ingestion of NaOH is to take in plenty of water.
c) The compound is not flammable
d) The chemicals that could produce a dangerous reaction with NaOH are acids
e) To handle small spills, irrigate the affected area with plenty water and use lab coats, gloves and eye wear when working with the solution.
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Answer:
if its a neutral atom there should be 6 electrons because there are 6 protons
Explanation:
I believe they are called Energy Levels or Energy Orbitals.
Explanation:
Sodium Chloride or NaCl is made up of two elements, sodium (or Na) and chlorine (or Cl). A molecule of sodium chloride, NaCl, consists of one atom each of sodium and chlorine. Hence, each molecule of NaCl has 2 atoms total.
Answer : The value of rate of reaction is 
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The given chemical equation is:
Rate law expression for the reaction is:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
As per question,
a = order with respect to 
= 2
b = order with respect to 
= 1
Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of rate of reaction by using the rate law expression.
Given :
k = rate constant = 
[NO] = concentration of NO = 
![[O_2]](https://tex.z-dn.net/?f=%5BO_2%5D)
= concentration of = 
Now put all the given values in the above expression, we get:
Hence, the value of rate of reaction is
