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4 years ago

7

Two tuning forks are played at the same time. One has a frequency of 176 Hz and the other is 178 Hz. How many beats per second a

re heard? 176 178 2 4

1 answer:

olya-2409 [2.1K]4 years ago

6 0

2 beats.........................................................

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3 years ago

Just before the ball leaves her hand, what is its centripetal acceleration?

erica [24]

A = $\frac{ v^{2} }{r}$ = ω²r

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3 years ago

Mars has twice the mass of Mercury and is 4 times further away from the Sun. Calculate theratio of the gravitational force from

svetoff [14.1K]

Answer:

F(Mars) = 2 G m M / (4 R)^2 force of Sun on Mars

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R = distance of Sun from Mercury, m = mass of Mercury

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3 years ago

Write a question you would like to see on a quiz to calculate NET FORCE.

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3 years ago

Three resistors are wired in parallel with a battery. Two of the resistors have resistances of 38.7 Q/ and 89.5 Q. The current i

Lina20 [59]

Answer:

$214.9 \Omega$

Explanation:

The three resistors are connected in parallel: this means that the potential difference across each resistor is the same as the voltage of the battery. This can be calculated using the information about the $38.7 \Omega$ resistor: in fact, since we know its resistance and the current flowing through it (0.155 A), we can find the potential difference across this resistor, which is equal to the voltage of the battery:

$V=IR=(0.155 A)(38.7 \Omega)=6.0 V$

We also know the total current in the circuit, 0.250 A. This means that we can find the total resistance of the circuit, using Ohm's law:

$R_{eq}=\frac{V}{I}=\frac{6.0 V}{0.250 A}=24 \Omega$

So now we now the total resistance and the resistance of two of the 3 resistors; therefore, we can find the resistance of the 3rd resistor:

$\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}\\\frac{1}{R_3}=\frac{1}{R_{eq}}-\frac{1}{R_1}-\frac{1}{R_2}=\frac{1}{24 \Omega}-\frac{1}{38.7\Omega}-\frac{1}{89.5\Omega}=0.00465 \Omega^{-1}\\R_3=\frac{1}{0.00465 \Omega^{-1}}=214.9 \Omega$

4 0

3 years ago