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ra1l [238]
4 years ago
11

A person bounces up and down on a trampoline, while always staying in contact with it. The motion is simple harmonic motion, and

it takes 2.65 s to complete one cycle. The height of each bounce above the equilibrium position is 36.0 cm. Determine (a) the amplitude and (b) the angular frequency of the motion. (c) What is the maximum speed attained by the person
Physics
1 answer:
soldi70 [24.7K]4 years ago
8 0

Answer with Explanation:

We are given that

Time period,T=2.65 s

a.Distance between the equilibrium position and the point at  maximum height is called amplitude.

Therefore, A=36 cm=\frac{36}{100}=0.36 m

 1 m=100 cm

b.Angular frequency,\omega=\frac{2\pi}{T}=\frac{2\pi}{2.65}=2.37 rad/s

c.Maximum speed,v_{max}=A\omega

Using the formula

Maximum speed,v_{max}=0.36\times 2.37=0.85 m/s

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A person sits on a freely spinning lab stool that has no friction in its axle. When this person extends her arms, A) her moment
julia-pushkina [17]

Answer:

B) her moment of inertia increases and her rotational kinetic energy decreases.

Explanation:Moment of Inertia is the term used to describe the rotation of an object in relationship to its own rotation,IT IS THE PRODUCT OF MASS AND THE SQUARE DISTANCE COVERED.

Moment of Inertia is also a resistance force which tend to oppose the impact of a turning force aimed at preventing its rotation about its axis. As the moment of Inertia increases her rotational kinetic energy will continue to decrease,due to the impact of the resistant or opposing force.

8 0
4 years ago
An automobile has a mass of 1200 kg. What is its kinetic energy, in kJ, relative to the road when traveling at a velocity of 50
nikdorinn [45]

Answer:

K.E = 463.04 k J

P = 23.14 Watt

Explanation:

given,

mass of automobile = 1200 kg

velocity = 50 km/h

             = 50 × 0.278

             = 13.9 m/s

kinetic energy = \dfrac{1}{2}mv^2

                        =\dfrac{1}{2}\times 1200 \times 13.9^2

        K.E = 115.93 k J

vehicle accelerated to velocity = 100 km/h

                                                    = 100 × 0.2778

                                                    = 27.78 m/s

kinetic energy = \dfrac{1}{2}mv^2

                        =\dfrac{1}{2}\times 1200 \times 27.78^2

        K.E = 463.04 k J

work done = change in kinetic energy

                   = 463.04 - 115.93

                   = 347.11 J

Power = \dfrac{work\ done}{time}

Power =\dfrac{347.11}{15}

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7 0
3 years ago
Four identical resistors have 12 ohm each. Find the equivalent resistance Req when : (a) all four of them are connected in serie
Elanso [62]

Answer:

(a): When the four resistors are connected in series the equivalent resistor value is Req= 48Ω

(b): when the four resistors are connected in parallel the equivalent resistor value is Req=3Ω

Explanation:

R=R1=R2=R3=R4= 12Ω

(a)

Req= R1+R2+R3+R4

Req= 48 Ω

(b)

Req= (1/12 * 4)⁻¹

Req= 3 Ω

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Do you think the benifits of nuclear power outweigh the potential drawbacks
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