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ra1l [238]
3 years ago
11

A person bounces up and down on a trampoline, while always staying in contact with it. The motion is simple harmonic motion, and

it takes 2.65 s to complete one cycle. The height of each bounce above the equilibrium position is 36.0 cm. Determine (a) the amplitude and (b) the angular frequency of the motion. (c) What is the maximum speed attained by the person
Physics
1 answer:
soldi70 [24.7K]3 years ago
8 0

Answer with Explanation:

We are given that

Time period,T=2.65 s

a.Distance between the equilibrium position and the point at  maximum height is called amplitude.

Therefore, A=36 cm=\frac{36}{100}=0.36 m

 1 m=100 cm

b.Angular frequency,\omega=\frac{2\pi}{T}=\frac{2\pi}{2.65}=2.37 rad/s

c.Maximum speed,v_{max}=A\omega

Using the formula

Maximum speed,v_{max}=0.36\times 2.37=0.85 m/s

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Many people who have contracted a disease called chicken pox were told by their doctors that they would never have this
vladimir1956 [14]

Answer:

Once you've had chickenpox you can't again.

Explanation: the virus remains inactive in your nerve tissue. Although it's unlikely you will get chickenpox again, the virus may reactivate later in life and cause a related condition called shingles.

5 0
3 years ago
An ultrasonic ruler, such as the one discussed in Example 4 in Section 16.6, displays the distance between the ruler and an obje
garik1379 [7]

Answer:

reading would be 5.413 m.

Explanation:

Given:-

- The actual distance from ruler to an object is d = 24.0 m

- The adiabatic bulk modulus, B = 2.37 *10^9 Pa

- The density of seawater, ρ = 1025 kg/m^3

- The preset value of speed of sound in air, v_th = 343 m/s.

Find:-

Determine the distance reading that the ruler displays.

Solution:-

- We will first determine the actual speed of the sound ( v_a) in sea-water which can be determined from the following formula:

                            v_a = √ (B /  ρ )

- Plug in the values in the relationship above and compute v_a:

                            v_a = √ ( 2.37 *10^9 /  1025  )        

                            v_a = 1520.59038 m/s

- The time taken (t) for for the sound to travel from source(ruler) to an object which is d distance away.

                            d = v_a*t

                            t = d / v_a

                            t = 24.0 / 1520.59038

                            t = 0.01578 s

- The distance reading on the ruler would be preset speed (v_th) of sound in air multiplied by the time taken(t).

                           reading = v_th*t

                           reading = (343)*(0.01578)

                                         = 5.413 m

6 0
3 years ago
DNA’s diameter is 0.000000002 meters. What is this measurement in scientific notation? a. 2.0 x 109 m
NARA [144]

Answer:

0.000000002 m=2.0*10⁻⁹ m

Explanation:

Scientific notation allows us to write very large or very small numbers in abbreviated form. This notation simply consists of multiplying by a power of base 10 with a positive or negative exponent.

A number written in scientific notation has the form:

a*10ⁿ

where:

  • the coefficient a has a value such that 1 ≤ a <10
  • n is an integer.  Represents the number of times the decimal point is shifted. It is always a whole number, positive if it is shifted to the left, negative if it is shifted to the right.

So to write the number 0.000000002 in scientific notation, the following steps are performed:

  • The decimal point is moved to the right as many spaces until it reaches the right of the first digit.
  • This number is then written, which will be the coefficient a in the expression of the previous product. So a=2.0
  • The base 10 is written with the exponent equal to the number of spaces that the comma moves. So n=9. But this is a negative number because the comma shifts to the right.

So, you get: <u><em>0.000000002 m=2.0*10⁻⁹ m</em></u>

3 0
3 years ago
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Tema [17]

Answer:

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4 0
3 years ago
Read 2 more answers
The human ear canal is about 2.9 cm long and can be regarded as a tube open at one end and closed at the eardrum. What is the fu
solniwko [45]

The frequency of the human ear canal is 2.92 kHz.

Explanation:

As the ear canal is like a tube with open at one end, the wavelength of sound passing through this tube will propagate 4 times its length of the tube. So wavelength of the sound wave will be equal to four times the length of the tube. Then the frequency can be easily determined by finding the ratio of velocity of sound to wavelength. As the velocity of sound is given as 339 m/s, then the wavelength of the sound wave propagating through the ear canal is  

Wavelength=4*Length of the ear canal

As length of the ear canal is given as 2.9 cm, it should be converted into meter as follows:

wavelength = 4*2.9*10^{-2} =0.116

Then the frequency is determined as

f=c/λ=339/0.116=2922 Hz=2.92 kHz.

So, the frequency of the human ear canal is 2.92 kHz.

4 0
3 years ago
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