A 0.91 kg ball and a 2 kg ball are connected by a 0.95 m long rigid, massless rod. The rod is rotating clockwise about its cente
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(a) The skater covers a distance of S=50 m in a time of t=12.1 s, so its average speed is the ratio between the distance covered and the time taken:
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.
(b) The initial speed of the skater is
while the final speed is
and the time taken to accelerate to this velocity is t=2 s, so the acceleration of the skater is given by
(c) The initial speed of the skater is
while the final speed is
since she comes to a stop. The distance covered is S=8 m, so we can use the following relationship to find the acceleration of the skater:
from which we find
where the negative sign means it is a deceleration.
10.67m/s²
32N
Explanation:
Given parameters:
Mass of the body = 3kg
velocity of the mass = 4m/s
radius of circle = 0.75m
Unknown:
centripetal acceleration = ?
centripetal force = ?
Solution:
The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:
Centripetal acceleration =
v is the velocity of the body
r is the radius of the circle
putting in the parameters:
Centripetal acceleration =
Centripetal acceleration = 10.67m/s²
Centripetal force = m
m is the mass
Centripetal force = mass x centripetal acceleration
= 3 x 10.67
= 32N
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