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3 years ago

A ball is thrown at 25 m/s at an angle of 55 degrees.

Physics

1 answer:

yuradex [85]3 years ago

4 0

Answer:65 seconds

Explanation:just had the quiz

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Daffy Duck is standing 6.8 m away from Minnie Duck. The attractive gravitational force between them is 5.4x10-8 N. If Daffy Duck

artcher [175]

Answer:

432.78 Kg

Explanation:

From the question given above, the following data were obtained:

Distance apart (r) = 6.8 m

Force of attraction (F) = 5.4×10¯⁸ N

Mass of Daffy Duck (M₁) = 86.5 kg

Mass of Minnie Duck (M₂) =?

NOTE: Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

The mass of Minnie Duck can be obtained as follow:

F = GM₁M₂ / r²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 6.8²

5.4×10¯⁸ = 6.67×10¯¹¹ × 86.5 × M₂ / 46.24

Cross multiply

6.67×10¯¹¹ × 86.5 × M₂ =5.4×10¯⁸ × 46.24

Divide both side by 6.67×10¯¹¹ × 86.5

M₂ = 5.4×10¯⁸ × 46.24 / 6.67×10¯¹¹ × 86.5

M₂ = 432.78 Kg

Therefore, the mass of Minnie Duck is 432.78 Kg

8 0

3 years ago

You have decided to study the effect of loud noise on plant growth. You put one plant in a quiet room and the other plant in you

Aleksandr [31]

B. control

also known as constant

7 0

3 years ago

The diagram shows movement of thermal energy. At bottom a fire has red curved lines labeled Y with arrowheads pointing upward to

Pepsi [2]

Answer:

X and Z

Explanation:

Conduction occurs through direct physical contact. Heat transferred from the pot to the handle, and from the handle to the hand, are both examples of conduction.

6 0

3 years ago

Read 2 more answers

What is the primary source of a sound?

brilliants [131]

Answer:

A vibration is the primary source of a sound.

8 0

3 years ago

6. Aaron will run from home at y mph and walk back at x mph. how much distance does he need to travel to spend a total of t hour

Kisachek [45]

Answer:

Total distance, $d=\dfrac{xyt}{(x+y)}$

Explanation:

It is given that,

Speed of Aaron from home is y mph and walk back at x mph. Let t is the total time he spend in walking and jogging. Let d is the distance covered.

We he moves from home to destination, time is equal to, $\dfrac{d}{x}$

Similarly, when he move back to home, time taken is equal to $\dfrac{d}{y}$

Total time taken is equal to :

$\dfrac{d}{x}+\dfrac{d}{y}=t$

$d(\dfrac{1}{x}+\dfrac{1}{y})=t$

$d=\dfrac{t}{(\dfrac{1}{x}+\dfrac{1}{y})}$

$d=\dfrac{xyt}{(x+y)}$

So, the distance he speed in walking and jogging is $\dfrac{xyt}{(x+y)}$ . Hence, this is the required solution.

8 0

3 years ago