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12345 [234]
4 years ago
9

A rotating merry go-round makes one complete revolution in 4.2 s. (a) what is the linear speed of a child seated 1.3 m from the

center?
Physics
2 answers:
gregori [183]4 years ago
6 0
The radius, r, of the child from the center of the wheel is
r = 1.3 m

The wheel makes one revolution in 4.2 s. Its angular velocity is
ω = (2π rad)/(4.2 s) = 1.496 rad/s

The linear speed of the child is the tangential velocity, given by
v = rω
   = (1.3 m)*(1.496 rad/s)
   = 1.945 m/s

Answer: 1.95 m/s  (nearest hundredth)

Lera25 [3.4K]4 years ago
3 0
Remember in solving any Physics problem it is important to write all the given parameter. Given are 1 complete revolution of merry go-round or can be written as 1rev/s, this should be converted to radians, since it makes one complete revolution. Radius given equal to 1.3 m from the center. Simply follow the process,  ω=1rev/s x 2πrads/rev  ω=answer will in "rad/s" or cancel the unit "rev". The formula to follow is Speed=rω. just multiply radius and the angular speed. 
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Answer:

D. Opening the front door in winter to filter and clean warm ai

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All of the following are examples of ways to improve energy efficiency of heating systems, except _______.

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3 years ago
an apple in a tree has a gravitational potential energy of 175J and a mass of 0.36g . how high from the ground is the apple
Neko [114]
The equation for potential energy is denoted as; 

Pe = mgh,

where m = the mass, g = acceleration due to gravity, and h = vertical height of the apple. We are given the units for everything but height, which is also what we are solving for. We can then algebraically rearrange our initial equation to solve for h;

h = (Pe)/(mg)

Plug in your given units, and solve!





Post-check:

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