Answer: 234.4K
Explanation:
Given that,
Original volume of gas (V1) = 5.00 L
Original temperature of gas (T1) = 20.0°C
[Convert 20.0°C to Kelvin by adding 273
20.0°C + 273 = 293K]
New volume of gas (V2) = 4.0L
New temperature of gas (T2) = ?
Since volume and temperature are given while pressure is held constant, apply the formula for Charle's law
V1/T1 = V2/T2
5.00L/293K = 4.0L/T2
To get the value of T2, cross multiply
5.00L x T2 = 293K x 4.0L
5.00L•T2 = 1172L•K
Divide both sides by 5.00L
5.00L•T2/5.00L = 1172L•K/5.00L
T2 = 234.4K
Thus, the new temperature of the gas is 234.4 Kelvin
Answer is: D. The I⁻ ion and the positive end of a water molecule.
Dissociation of potassium iodide in water:
KI(aq) → K⁺(aq) + I⁻(aq).
Solvation is the interaction of solvent (water) with molecules or ions (in this example K⁺ and I⁻) in a solute.
Anion I⁻ has negative charge, so positive end (hydrogen atoms) of a water molecul attracts them.
Solvent (usually a liquid, but can also be a solid or a gas) is a substance that dissolves a solute.
Answer:
Please see the attached picture for the complete answer.
Explanation:
Non-metal atoms gain an electron, or electrons, from another atom to become >negatively charged ions.
The answer is c. hg (mercury)
