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2 years ago

If the specific heat of water is 1.0 calorie/gram°C, how many calories are required to raise 500 grams of water 10.0°C?

1 answer:

6 0

The amount of heat that is required to raise the temperature of a system is calculated by the expression:

Heat required = m Cp ΔT
Heat required = 500 g (1.0 calorie/gram °C) (10.0 <span>°C)
Heat required = 5000 calorie

The correct answer from the choices listed above is the second option.</span>

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bogdanovich [222]

Ultraviolet has a shorter wavelength than microwaves, so purple also has a shorter wavelength than red.

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3 years ago

What determines an object’s velocity?

joja [24]

Answer:

I think it's 3) speed and direction

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3 years ago

1. An airow is shot horizontally from a crossbow 1.5 m above the ground. The initial velocity is 45

Amanda [17]

Answer:

Time taken by the arrow to travel along to hit the ground is 0.55 seconds.

Explanation:

The only "force" acting on the "crossbow" to cause it to "hit" the ground is "gravity". There is no initial velocity downward when it shoot.

$d=v_{i} t+\frac{1}{2} t^{2}$

d = the displacement of the object

t = the time for which the object moved

a = acceleration of the object

$v_i$ = the initial velocity of the object

Given values

d = 1.5 m

t = unknown

$a=g=9.8 \mathrm{m} / \mathrm{s}^{2}$

$\mathrm{V}_{\mathrm{i}}=0 \mathrm{m} / \mathrm{s}$

$1.5 \mathrm{m}=0(\mathrm{t})+\frac{1}{2}\left(9.8 \mathrm{m} / \mathrm{s}^{2}\right) \mathrm{t}^{2}$

$1.5=0+4.9 \mathrm{t}^{2}$

$\mathrm{t}^{2}=\frac{1.5}{4.9}$

$t^{2}=0.306 \mathrm{s}$

Square root both sides

$t=\sqrt{0.306}$

t = 0.55 s

4 0

3 years ago

Debby and Ben took different routes to travel from Point A to Point E. Debby took the route along A, B, C, D, and E. Ben took th

svetlana [45]

Answer:

Ben's average speed was twice Debby's average speed.

Explanation:

Ben covered a total distance of 16 miles (10+4+2) and Debby covered 8 miles (3+2+2+1) which is half of what Ben covered. As they both reached the place in the same amount of time it tells us Ben was faster.

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3 years ago

Read 2 more answers

Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .

aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation: