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Anastasy [175]
3 years ago
15

Consider an experiment with a deck of 52 playing cards, in which there are 13 cards in each suit, two suits are black, and two s

uits are red. Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).
Mathematics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

<u>P (E1) = 1/2 or 50%</u>

<u>P (E2) = 3/13 or 23%</u>

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Number of playing cards = 52

Number of suits = 4

Number of cards per suit = 13

Number of black suits = 2

Number of red suits = 2

2.  Suppose E1 = the outcome is a red card and E2 = the outcome is a face card (K, Q, J). Determine P(E1 or E2).

P (E1) = Number of red cards/Total of playing cards

P (E1) = 26/52 = 1/2 = 50%

P (E2) = Number of face cards/Total of playing cards

P (E2) = 12/52 = 3/13 = 23%

Lady bird [3.3K]3 years ago
6 0

Answer:

outcomes of E1 = [1, 3, 5, 7, 9, 12, 14, 16, 18, 19, 21, 23, 25, 27, 30, 32, 34, 36]

outcomes of E2 = [1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35]

Step-by-step explanation:

PLATO

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community gym

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8 0
3 years ago
Wylie is renting a bicycle from a local shop that charges $5 to rent a helmet, plus an hourly rate of $8.50 for the bike. for ho
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47.50 = 8.50x + 5
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5 0
3 years ago
Factor 64b-16c to identify the equivalent expressions. *
scoray [572]

Answer:

The factored form of this would be 16(4b - c)

Step-by-step explanation:

In order to find this, look for the greatest common factor of 16 and 64. You can do this by listing out their factors. Once this is done and we identify 16 as the GCF, we can then put that on the outside of the parenthesis and divide all the terms inside by that number.

5 0
3 years ago
How much kinetic energy does a 80 kg man have while running at 1.5 M/S
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KE=1/2(m)(v)^2 


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7 0
4 years ago
In 2003 a town’s population was 1431. By 2007 the population had grown to 2134. Assume the population is changing linearly.How m
sergiy2304 [10]

We will have the following:

First, we will have that the population change by:

\Delta P=2134-1431\Rightarrow\Delta P=703

So, the population changed by 703 people.

It took the follwoing number of years to change from 1431 to 2134:

\Delta y=2007-2003\Rightarrow\Delta y=4

So, it took 4 years to changes from 1431 to 2134.

m=\frac{2134-1431}{2007-2003}\Rightarrow m=175.75

The average population growth per year is of 175.75 people per year.

The population in 2000 would have been:

P_{2000}=\frac{2000\cdot1431}{2003}\Rightarrow P_{2000}=1428.856715\ldots

\Rightarrow P_{2000}\approx1429

So, the population in 2000 would have been approximately 1429 people.

We will have that the equation for the population would be:

P=(\frac{2134-1431}{2007-2003})t+1429\Rightarrow P=\frac{703}{4}t+1429

So, the equation would be:

P=175.75t+1429

Now, we predict the number of people of the town in 2014:

P_{2014}=175.75(14)+1429\Rightarrow P_{2014}=3889.5

\Rightarrow P_{2014}\approx3890

So, there will be approximately 3890 people of the town in 2014.

3 0
1 year ago
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