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Vinvika [58]
3 years ago
7

Every spring has an equilibrium position. Which statements describe a spring at its equilibrium position? Check all that

Physics
2 answers:
alexgriva [62]3 years ago
8 0

Answer:

The elastic potential energy is zero.

The net force acting on the spring is zero.

Explanation:

The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.

Let's now analyze the different statements:

The spring constant is zero.  --> false. The spring constant is never zero.

The elastic potential energy is at a maximum  --> false. The elastic potential energy of a spring is given by

E=\frac{1}{2}kx^2

where k is the spring constant and x the displacement. Therefore, the elastic potential energy is maximum when x, the displacement, is maximum.

The elastic potential energy is zero.  --> true. As we saw from the equation above, the elastic potential energy is zero when the displacement is zero (at the equilibrium position).

The displacement of the spring is at a maxi num  --> false, for what we said above

The net force acting on the spring is zero. --> true, as the spring is neither compressed nor stretched

Umnica [9.8K]3 years ago
7 0

Answer:

the person from above is correct

Explanation:

i just took the quiz

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Answer:

C. The total momentum of a set of objects is the same before and

after a collision.

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4 years ago
When a space shuttle was launched, the astronauts aboard experienced and acceleration of 29.0 m/s. If one of the astronauts had
ankoles [38]

             Net force = (mass) · (acceleration)

                           = (69 kg) · (29 m/s²)

                           = (69 · 29) · (kg·m/s²)

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4 years ago
The left end of a long glass rod 8.00 cm in diameter and with an index of refraction of 1.60 is ground and polished to a convex
lesya692 [45]

Answer:

A) 0.1477

B) 0.65388 mm

C) object is inverted

Explanation:

The formula for object - image relationships for spherical reflecting surface is given as;

n1/s + n2/s' = = (n2 - n1)/R

Where;

n1 & n2 are the Refractive index of both surfaces

s is the object distance from the vertex of the spherical surface

s' is the image distance from the vertex of the spherical surface

R is the radius of the spherical surface

We are given;

index of refraction of glass; n2 = 1.60

s = 24 cm = 0.24 m

R = 4 cm = 0.04 m

index of refraction of air has a standard value of 1. Thus; n1 = 1

a) So, making s' the subject from the initial equation, we have;

s' = n2/[((n2 - n1)/R) - n1/s]

Plugging in the relevant values, we have;

s' = 1.6/[((1.6 - 1)/0.04) - 1/0.24]

s' = 0.1477

b) The formula for lateral magnification of spherical reflecting surfaces is;

m = -(n1 × s')/(n2 × s) = y'/y

Where;

m is the magnification

n1, n2, s & s' remain as earlier explained

y is the height of the object

y' is the height of the image

Making y' the subject, we have;

y' = -(n1 × s' × y)/(n2 × s)

We are given y = 1.7 mm = 0.0017 m and all the other terms remain as before.

Thus;

y' = -(1 × 0.1477 × 0.0017)/(1.6 × 0.24)

y' = - 0.00065388021 m = -0.65388 mm

C) since y' is negative and y is positive therefore, m = y'/y would result in a negative value.

Now, in object - image relationships for spherical reflecting surface, when magnification is positive, it means the object is erect and when magnification is negative, it means the object is inverted.

Thus, the object is inverted since m is negative.

6 0
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How can you tell the direction a river flows
NARA [144]

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4 0
3 years ago
What is the speed of a 6-kg ball with a momentum of 72 kg∙m/s?
Nookie1986 [14]
The momentum of a moving object is given by:
p=mv
where m is the mass of the object and v its speed.

In this problem, the ball has a mass of m=6 kg and its momentum is p=72 kg m/s, so we can rearrange the previous equation to find the speed of the ball:
v= \frac{p}{m}= \frac{72 kg m/s}{6 kg}=12 m/s
6 0
3 years ago
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