The pressure needed : 800 kPa
<h3>Further explanation</h3>Given
V₁ = 0.4 m³
P₁ = 100 kPa
T₁ = 20 + 273 = 293 K
V₂ = 0.05 m³
T₂ = T₁ = 293 K
Required
The final pressure(P₂)
Solution
Boyle's Law
At a fixed temperature, the gas volume is inversely proportional to the pressure applied
Input the value :
P₂=P₁V₁/V₂
P₂=100 x 0.4 / 0.05
P₂=800 kPa
Explanation:
It is given that,
When the front wheels are over the scale, the weight recorded by the scale is 5800 N, F₁ = 5800 N
When the rear wheels are over the scale, the scale reads 6500 N, F₂ = 6500
The distance between the front and rear wheels is measured to be 3.20 m, x₂ = 3.2 m
We need to find the location of center of mass behind the front wheels. Let the center of is located at a distance of x₁. Thus balancing the torques we get :
On solving the above equation we get, x₂ = 1.69 m
So, the center of mass is located at a distance of 1.69 meters behind the front wheels.
Answer:
v = 10 m/s
Explanation:
We have,
Our initial velocity is 20 m/s
Our acceleration,
It is required to find the velocity after 2 seconds. It is a concept based on equation of kinematics. Using first equation:
Plugging all the known values
So, our final velocity is 10 m/s.