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3 years ago

13

With a doctor’s permission, how many servings of the product could a person eat before reaching 100 percent of their allowable d

aily intake for cholesterol?

1 answer:

bogdanovich [222]3 years ago

7 0

About approximately 3 servings.

Hope this helped! :)

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In one hour Earth receives enough solar energy to meet the energy needs of the world for

erastova [34]

I have read that it is enough energy to power the needs of civilization for an entire year.

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2 years ago

An object moves on a trajectory given by Bold r left parenthesis t right parenthesis equals left angle 10 cosine 6 t comma 10 si

spayn [35]

Answer:

10

Explanation:

(r) = <10 cos 6t, 10 Sin 6t>

The distance traveled by the object is the magnitude of vector r.

The magnitude of vector r is given by

$r = \sqrt{(10 Cos 6t)^{2}+(10 Sin 6t)^{2}}$

$r =10 \sqrt{(Cos^{2} 6t)+(Sin^{2} 6t)$

r = 10

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2 years ago

Oxygen is needed by all cells of most organisms for the release of

pashok25 [27]

Answer:

From the SUN

Explanation:

Hope it helps!!!

Follow me if you want :)

7 0

1 year ago

A rifle fires a 2.90 x 10-2-kg pellet straight upward, because the pellet rests on a compressed spring that is released when the

iren2701 [21]

Answer: 586.60N/m

Explanation:

In this scenario, the elastic potential energy of the spring is converted into potential energy.

0.5*K*x^2 = mgh

Thus K = 2mgh/x^2

=(2*2.90*10^-2*9.8*7.23)/(8.37*10^-2)^2

=586.599

Therefore K = 586.60N/m

7 0

3 years ago

Read 2 more answers

a load of 800 newton is lifted by an effort of 200 Newton. if the load is placed at a distance of 10 cm from the fulcrum. what w

nataly862011 [7]

Answer:

40 cm

Explanation:

We are given that

Load=800 N

Effort=200 N

Load distance=10 cm

We have to find the effort distance.

We know that

$load\times load\;distance=Effort\times effort\;distance$

Using the formula

$800\times 10=200\times effort\;distance$

Effort distance= $\frac{800\times 10}{200}$

Effort distance= $\frac{8000}{200}$

Effort distance=40 cm

Hence, the effort distance will be 40 cm.

7 0

2 years ago