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grigory [225]
3 years ago
7

Identify a syntax used to create a spinner control using an input element. a. b. c. d.

Computers and Technology
1 answer:
Lorico [155]3 years ago
6 0

Answer:

Option A:

<input name="name" id="id" type="number" value="value" step="value" min="value" max="value" />

Explanation:

Spinner control is a graphical control element where user can adjust the value by pressing up or down arrow button. An example is given in the attached image.

In HTML, one of the key attributes we must use to create a spinner control is "step". The attribute "step" is required to specify the interval of the step value when user press the up or down arrow button.

If we set the attribute values as follows:

  • type = "number"
  • value = 2
  • min = 0
  • max = 10

The setting above will give a spinner control with a range of legal numbers between 0, 2, 4, 6, 8 and 10.

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A common preprocessing step in many natural language processing tasks is text normalization, wherein words are converted to lowe
Arturiano [62]

Answer:

def normalize(text):

   text = text.lower()

   text = text.split()

   return text

Explanation:

The functiinfunction is provided with an input text when called upon, then it changes every character in the text into lower case and split each word with a space.

4 0
3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
The function below takes a single string parameter: sentence. Complete the function to return everything but the middle 10 chara
dolphi86 [110]

Answer:

def get_middle_ten(sentence):

   ind = (len(sentence) - 12) // 2

   return sentence[ind:ind + 12]

# Testing the function here. ignore/remove the code below if not required

print(get_middle_twelve("abcdefghijkl"))

print(get_middle_twelve("abcdefghijklmnopqr"))

print(get_middle_twelve("abcdefghijklmnopqrst"))

7 0
3 years ago
What is the largest decimal value you can represent, using a 86-bit signed<br> integer?
Nataly [62]

Answer:

2^{85}-1

Explanation:

Considering the number are stored using binary notations.

If there are total 86 bits and 1 bit is used as sign bit. Then in total one can have 2^{85} bit combinations since a bit can be either stored as 0 or as 1.

Therefore,  the largest number that can be stored will be 2^{85}-1.

To understand it in better way let's scale down the problem to 3 bits representation. The largest number that can be stored using 3 bits is 111 which in decimal form is 7 and is equal to 2^{3}-1.

4 0
3 years ago
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svlad2 [7]
A copy and paste would be fastest and easiest. As you can pinpoint the exact location to where you want the picture to be. 
5 0
3 years ago
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