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Marysya12 [62]
3 years ago
8

When an electric field is applied to a metallic crystal, the movement of electrons is _____

Chemistry
2 answers:
Soloha48 [4]3 years ago
8 0

random.

Hope this helps!

Anvisha [2.4K]3 years ago
4 0

Answer: directional

(i have to write something to make the character minimum. don't mind this.)

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Is powdered drink and water a mixture or a solution
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It is a homogenous solution because the powder is suspended in the liquid and there is no difference between any parts of it.
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A 40.27 g sample of a substance is initially at 24.8 °c. after absorbing 2099 j of heat, the temperature of the substance is 148
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Q = mCΔT
Q is heat in joules, m is mass, C is specific heat, and delta T is change in temp

2099 J = (40.27g)(C)(148.5 - 24.8) = .421 J / gram K
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3 years ago
What shape would a molecule of carbon tetrachloride have?
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Answer:

Tetrahedral

Explanation:

For the repulsion of the free electron pair theory, the shape of a molecule will be to repel the bonds and the free electrons on the central atom. In a molecule of carbon tetrachloride, the central atom (C) has no free electrons, so, the shape that repels better the charge is tetrahedral, as shown below.

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3 years ago
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Calculate how many moles of element Q are in 23.53 g of element Q.
pogonyaev

Answer:

0.579 moles

Explanation:

Moles = 23.53/40.64

= 0.5789 moles

7 0
3 years ago
What is the mass of a sample of metal that is heated from 58.8°C to 88.9°C with a
Vadim26 [7]

Answer:

\boxed {\boxed {\sf 333 \ grams}}

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

Q= mc \Delta T

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

  • ΔT= final temperature - initial temperature

The sample was heated <em>from </em> 58.8 degrees Celsius to 88.9 degrees Celsius.

  • ΔT= 88.9 °C - 58.8 °C = 30.1 °C

Now we know three variables:

  • Q= 4500.0 J
  • c= 0.4494 J/g°C
  • ΔT = 30.1 °C

Substitute these values into the formula.

4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)

Multiply on the right side of the equation. The units of degrees Celsius cancel.

4500.0 \ J = m (13.52694 J/g)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}

The units of Joules cancel.

\frac {4500.0 \ J }{13.52694 J/g}= m

332.6694729 \ g =m

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

333 \ g \approx m

The mass of the sample of metal is approximately <u>333 grams.</u>

8 0
3 years ago
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