Question

A container of gas is initially at 0.25 atm and 0 ˚C. What will the pressure be at 125 ˚C?

Answer 1

Answer:

0.37atm

Explanation:

Given parameters:

Initial pressure  = 0.25atm

Initial temperature  = 0°C  = 273K

Final temperature  = 125°C  = 125 + 273  = 398K

Unknown:

Final pressure  = ?

Solution:

To solve this problem, we use a derivative of the combined gas law;

           $\frac{P1}{T1}$  = $\frac{P2}{T2}$

  P and T are pressure and temperature

  1 and 2 are initial and final values

        $\frac{0.25}{273}$   = $\frac{P2}{398}$  

         P2  = 0.37atm