18)
a. Ra
d. Ag
19)
a. C
b. Br
c. Mg
20)
a. S
b. Br
c. O
Sorry wasn’t sure about some of them in #18
Hope the notes are helpful.
Answer:
22.8 L
Explanation:
Step 1: Given data
- Moles of the gas (n): 1.35 mol
- Pressure of the gas (P): 1.30 atm
- Ideal gas constant (R): 0.0821 atm.L/mol.K
Step 2: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15 = -6 + 273.15 = 267 K
Step 3: Calculate the volume of the gas
We will use the ideal gas equation.
P × V = n × R × T
V = n × R × T / P
V = 1.35 mol × (0.0821 atm.L/mol.K) × 267 K / 1.30 atm
V = 22.8 L
Answer:
n = 11.45 mol
Explanation:
Given data:
Number of moles = ?
Volume of gas = 98 L
Pressure = 2.8 atm
temperature = 292 K
Solution:
The given problem will be solve by using general gas equation,
PV = nRT
P= Pressure
V = volume
n = number of moles
R = general gas constant = 0.0821 atm.L/ mol.K
T = temperature in kelvin
2.8 atm × 98 L = n × 0.0821 atm.L/ mol.K × 292 K
274.4 atm.L = n × 23.97atm.L/ mol
n = 274.4 atm.L /23.97atm.L/ mol
n = 11.45 mol
8.Carbonate tetranitride
9.Zinc chloride
10.Sodium cyanide
11.Magnesium Phosphate
Answer:
Explanation:
i’m not sure but I think it’s 7648%
