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Vika [28.1K]
3 years ago
7

What is a atomic bond ​

Chemistry
2 answers:
joja [24]3 years ago
4 0

Answer: A bond formed between atoms due to sharing or complete transfer of electrons is termed as "atomic bond". These are the intramolecular forces that hold atoms together in molecules.

zalisa [80]3 years ago
3 0
1.Electrons can be transferred from one atom to another.
2.Electrons can be shared between neighbouring atoms.
3.Electrons can be shared with all atoms in a material.
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Allotropes are elements on the periodic table that have more than one crystalline form . There are three forms of the element carbon : Diamond, Graphite, and Fullerenes. Isotopes are atoms of the same element with the same atomic number but have a different mass number.
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Which two celestial bodies orbit the Sun?
tiny-mole [99]
Number 1 is Comets and asteroids
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Read 2 more answers
N₂O(g) + 3 H₂(g) N₂H4(1) + H₂O(1) AH = -317 kJ/mol
docker41 [41]

Answer:

A

Explanation:

Recall that Δ<em>H</em> is the sum of the heats of formation of the products minus the heat of formation of the reactants multiplied by their respective coefficients. That is:


\displaystyle \Delta H^\circ_{rxn} = \sum \Delta H^\circ_{f} \left(\text{Products}\right) - \sum \Delta H^\circ_{f} \left(\text{Reactants}\right)

Therefore, from the chemical equation, we have that:


\displaystyle \begin{aligned} (-317\text{ kJ/mol}) = \left[\Delta H^\circ_f \text{ N$_2$H$_4$} +  \Delta H^\circ_f \text{ H$_2$O}  \right]   -\left[3 \Delta H^\circ_f \text{ H$_2$}+\Delta H^\circ_f \text{ N$_2$O}\right] \end{aligned}

Remember that the heat of formation of pure elements (e.g. H₂) are zero. Substitute in known values and solve for hydrazine:

\displaystyle \begin{aligned} (-317\text{ kJ/mol}) & = \left[ \Delta H^\circ _f \text{ N$_2$H$_4$} + (-285.8\text{ kJ/mol})\right] -\left[ 3(0) + (82.1\text{ kJ/mol})\right] \\ \\ \Delta H^\circ _f \text{ N$_2$H$_4$} & = (-317 + 285.8 + 82.1)\text{ kJ/mol} \\ \\ & = 50.9\text{ kJ/mol} \end{aligned}

In conclusion, our answer is A.

5 0
2 years ago
Calculate the number of molecules present in 0.5 mole of water​
Aleksandr-060686 [28]

Explanation:

Mole = 0.5 = n/NA

n = no. of molecule

NA = avogadro number = 6.023x 10^23

so

N/NA = 0.5

N = 0.5 x 6.023 x 10^23

N = 3.0115 x 10^23

6 0
3 years ago
He chemical formula for lithium hydride is LiH A chemist determined by measurements that 0.0800 moles of lithium hydride partici
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Answer:

Mark me brainlist I will then answer in comment

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