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slamgirl [31]
3 years ago
11

In the solar panel system presented in the video which of the following was necessary to generate usable electrical current for

a home
Physics
1 answer:
Leviafan [203]3 years ago
5 0
The answer is DC power had to be converted in AC.

DC power is not usually in home. DC current must be converted to to AC, which is the standard in homes and to avoid short circuits. 

DC or direct current explains the basic idea of electricity as a flow of electrons.
AC, also known as alternating current, electricity switches direction  around 50-60 times each second. In here, electrons do not necessarily have to run in circles to transport energy, they simply run on the spot.
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A neutral atom contains 8 protons 9 neutrons, and 8 electrons the atom must be A. A oxygen isotope. B. A nitrogen isotope. C. A
Harrizon [31]

Answer:

A an Oxygen isotope

Explanation:

The number of protons is the Same as the atomic number

The atomic number is 9 is the atom has 9 protons

Thus, the atom is an oxygen isotope

6 0
3 years ago
Read 2 more answers
A cello string vibrates in its fundamental mode with a frequency of 335 1/s. The vibrating segment is 28.5 cm long and has a mas
Inga [223]

Answer:

The tension in string is found to be 188.06 N

Explanation:

For the vibrating string the fundamental frequency is given as:

f1 = v/2L

where,

f1 = fundamental frequency = 335 Hz

v = speed of wave

L = length of string = 28.5 cm = 0.285 m

Therefore,

v = f1 2L

v = (335 Hz)(2)(0.285)

v = 190.95 m/s

Now, for the tension:

v = √T/μ

v² = T/μ

T = v² μ

where,

T = Tension

v = speed = 190.95 m/s

μ = linear mass density of string = mass/L = 0.00147 kg/0.285 m = 5.15 x 10^-3 kg/m

Therefore,

T = (190.95 m/s)²(5.15 x 10^-3 kg/m)

<u>T = 188.06 N</u>

4 0
2 years ago
Read 2 more answers
Bowling balls are roughly the same size, but come in a variety of weights. Given its official radius of roughly 0.110 m, calcula
velikii [3]

Answer:

6.1328 kg

60.16284 N

Explanation:

r = Radius of ball = 0.11 m

\rho = Density of fluid = 1.1\times 10^3\ kg/m^3 (Assumed)

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of ball

V = Volume of ball = \frac{4}{3}\pi r^3

The weight of the bowling ball will balance the buouyant force

W=F_b\\\Rightarrow mg=V\rho g\\\Rightarrow m=\frac{V\rho g}{g}\\\Rightarrow m=V\rho\\\Rightarrow m=\frac{4}{3}\pi 0.11^3\times 1.1\times 10^3\\\Rightarrow m=6.1328\ kg

The mass of the bowling ball will be 6.1328 kg

Weight will be 6.1328\times 9.81=60.16284\ N

5 0
3 years ago
A 0.55 kg projectile is launched from the edge of a cliff with an initial kinetic energy of 1550 J and at its highest point is 1
SCORPION-xisa [38]

Answer:

a). 53.78 m/s

b) 52.38 m/s

c) -75.58 m

Explanation:

See attachment for calculation

In the c part, The negative distance is telling us that the project went below the lunch point.

5 0
2 years ago
Instantaneous angular speed is: Group of answer choices the rate at which the angular acceleration is changing total angular dis
Ludmilka [50]

Answer: magnitude of the instantaneous angular velocity

Explanation:

Instantaneous angular speed is refered to as the magnitude of the instantaneous angular velocity. We should note that the instantaneous angular velocity is the rate that has to do with the rotation of an object in circular path.

5 0
3 years ago
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