Answer:3,45 x 10^9 N
Explanation: We have considered the total charge for each coin , this is the total atoms x 29 electrons for cooper and multiplier by electron charge, the total charge for each coin is 0,464 C
Finally we use the Coulomb law,
F=k Q/ (r)^2
Answer:
The speed of the 270g cart after the collision is 0.68m/s
Explanation:
Mass of air track cart (m1) = 320g
Initial velocity (u1) = 1.25m/s
Mass of stationary cart (m2) = 270g
Velocity after collision (V) = m1u1/(m1+m2) = 320×1.25/(320+270) = 400/590 = 0.68m/s
You could certainly have some good easy going carefree conversation with your sister or your cousin at dinner or at a movie, but relative dating is not an effective way to get serious and find a life partner.
Answer:
a) v₂ = 4.2 m/s
b) v₂ = 5 m/s
Explanation:
a)
We will use the law of conservation of momentum here:
![m_1u_1+m_2u_2=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3Dm_1v_1%2Bm_2v_2)
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0.8 m/s
v₂ = speed of second after before collsion = ?
Therefore,
![(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0.8\ m/s)+(1.8\ kg)(v_2)\\v_2 = 5\ m/s - 0.8\ m/s](https://tex.z-dn.net/?f=%281.8%5C%20kg%29%285%5C%20m%2Fs%29%2B%281.8%5C%20kg%29%280%5C%20m%2Fs%29%3D%281.8%5C%20kg%29%280.8%5C%20m%2Fs%29%2B%281.8%5C%20kg%29%28v_2%29%5C%5Cv_2%20%3D%205%5C%20m%2Fs%20-%200.8%5C%20m%2Fs)
<u>v₂ = 4.2 m/s</u>
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b)
We will use the law of conservation of momentum here:
![m_1u_1+m_2u_2=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3Dm_1v_1%2Bm_2v_2)
where,
m₁ = m₂ = mass of bowling pin = 1.8 kg
u₁ = speed of first pin before collsion = 5 m/s
u₂ = speed of second pin before collsion = 0 m/s
v₁ = speed of first pin after collsion = 0 m/s
v₂ = speed of second after before collsion = ?
Therefore,
![(1.8\ kg)(5\ m/s)+(1.8\ kg)(0\ m/s)=(1.8\ kg)(0\ m/s)+(1.8\ kg)(v_2)](https://tex.z-dn.net/?f=%281.8%5C%20kg%29%285%5C%20m%2Fs%29%2B%281.8%5C%20kg%29%280%5C%20m%2Fs%29%3D%281.8%5C%20kg%29%280%5C%20m%2Fs%29%2B%281.8%5C%20kg%29%28v_2%29)
<u>v₂ = 5 m/s</u>
Answer:
Explanation:
To describe the motion of any object, we must be able to describe its position x. It reflects it at any particular time. In other words, we need to specify its position relative to the conventional frame of reference.
I hope it helps! ≧◉◡◉≦