Answer:
7.74m/s
Explanation:
Mass = 35.9g = 0.0359kg
A = 39.5cm = 0.395m
K = 18.4N/m
At equilibrium position, there's total conservation of energy.
Total energy = kinetic energy + potential energy
Total Energy = K.E + P.E
½KA² = ½mv² + ½kx²
½KA² = ½(mv² + kx²)
KA² = mv² + kx²
Collect like terms
KA² - Kx² = mv²
K(A² - x²) = mv²
V² = k/m (A² - x²)
V = √(K/m (A² - x²) )
note x = ½A
V = √(k/m (A² - (½A)²)
V = √(k/m (A² - A²/4))
Resolve the fraction between A.
V = √(¾. K/m. A² )
V = √(¾ * (18.4/0.0359)*(0.395)²)
V = √(0.75 * 512.53 * 0.156)
V = √(59.966)
V = 7.74m/s
Bob's average speed was 80 m/s.
His average velocity was 40 m/s East.
The magnitude of his velocity was almost 4 times as fast as Usain Bolt's world record in the 100 meters, or about 89 mph. His speed was double that.
Im pretty sure its Rolling friction also know as rolling resistance
Answer:
Final speed of striped ball is 3 m/s in left direction .
Explanation:
Given :
Two billiard ball with the same mass moves toward the left at the same speed 3 m/s .
Let , us assume right hand side direction to be positive and left hand side direction to be negative .
Also , let speed of ball after collision is (striped ball ) u and (solid ball) v .
It is also given that the collision is elastic .
Therefore , kinetic energy is conserved .
...... ( 1 )
Also , by conserving linear momentum .
We get :
...... ( 2 )
Putting value of u from equation 2 to equation 1 .
We get :
And , u = -3 m/s .
Therefore , final speed of striped ball is 3 m/s in left direction .
Hence , this is the required solution .
Answer:
t = 20s
Explanation:
In order for the police car to capture the other car, both cars must travel the same length.
The distance traveled by the first vehicle is:
S = ^ Vt = 40t, where t represents the elapsed time and V the vehicle speed.
The distance traveled by the police car is:
S = at ^ 2/2 = 2t ^ 2, where t represents the elapsed time, a is the acceleration of the car.
As the distances traveled are equal:
40t = 2t ^ 2 in this way t = 20s
