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gizmo_the_mogwai [7]
3 years ago
6

What is the correct answer

Physics
1 answer:
posledela3 years ago
6 0

Answer:

D and compound

Explanation:

because N2 is = to a compound

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What does it mean for PE to be dependent on the reference level?
Anastasy [175]

Answer:

The potential energy of an object is the energy possessed by the object due to its position in a gravitational field.

Mathematically, it is given by:

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity at the location of the object

h is the height of the object

As we can see, the potential energy depends on the height of the object, h.

However, this height is relative, since it can be measured using different reference levels.

Generally, the reference level is taken to be the ground; so for example, an object located at the top of a cliff 40 m above the ground, has

h = 40 m

But this value is of course relative, since we can also take the reference level to be the top of the cliff, so in that case, we would have

h = 0

3 0
3 years ago
Radio waves heading upward from Earth often bounce off the
charle [14.2K]

Answer:

Radio waves heading upward from Earth often bounce off the thermosphere-D.

7 0
3 years ago
Read 2 more answers
What kind of thermal radiation does the earth emit?
Alex

I would think it's generated by thermal motion of charged particles in matter

7 0
4 years ago
A 0.5kg ball sits on top of a 20m high ramp. What is the potential energy of the ball?
Evgesh-ka [11]
Mass = 0.5 kg
H = 20m
G = 9.8 m/s^2

U (Potential energy) = M×g×h
= 0.5 × 9.8 × 20 = 98 J
3 0
4 years ago
A 1.89 kg object on a frictionless horizontal track is attached to the end of a horizontal spring whose force constant is 4.77 N
Maksim231197 [3]

Answer:

Magnitude F(t)=26.6 N

Direction: -x

Explanation:

Given data

Spring constant K=4.77 N/m

Mass m=1.89 kg

Displace A=5.56m

Time t=3.96s

To find

Magnitude of force F

Solution

The angular frequency is given as

w=\sqrt{\frac{K}{m} } \\w=\sqrt{\frac{4.77N/m}{1.89kg} }\\w=1.59rad/s

Force on object is

F(t)=-mAw^{2}Cos(wt)

Substitute given values

So

F(t)=-(1.89kg)(5.56m)(1.59rad/s)^{2}Cos(1.59*3.96)\\F(t)=-26.6N

So

Magnitude F(t)=26.6 N

Direction: -x

4 0
3 years ago
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