Answer:
The speed of the object is (
)m/s
The magnitude of the acceleration is 4.00m/s²
Explanation:
Given - position vector;
r = (2.0 + 3.00t)i + (3.0 - 2.00t²)j -------------------(i)
To get the speed vector (
), take the first derivative of equation (i) with respect to time t as follows;
= 
= ![\frac{d[(2.0 + 3.00t)i + (3.0 - 2.00t^2)j] }{dt}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5B%282.0%20%2B%203.00t%29i%20%2B%20%283.0%20-%202.00t%5E2%29j%5D%20%20%7D%7Bdt%7D)
= ------------------------(ii)
To get the acceleration vector (
), take the first derivative of the speed vector in equation(ii) as follows;
j
The magnitude of the acceleration |a| is therefore given by
|a| = |-4.00|
|a| = 4.00 m/s²
In conclusion;
the speed of the object is ()m/s
the magnitude of the acceleration is 4.00m/s²
Answer:
Answer below!!!!
Explanation:
Convection is the transfer of thermal energy by particles moving through a fluid.
Hope I Helped!!!
;)
Multiply by (1000 meters / 1 km).
Then multiply by (1 hour / 3600 seconds).
Both of those fractions are equal to ' 1 ', because the top
and bottom numbers are equal, so the multiplications
won't change the VALUE of the 72 km/hr. They'll only
change the units.
(72 km/hour) · (1000 meters / 1 km) · (1 hour / 3600 seconds)
= (72 · 1000 / 3600) (km·meter·hour / hour·km·second)
= 20 meter/second
Answer:
2 m/s^2
Explanation:
a = v^2/r
a = (10m/s)^2 / 50m
a = 2 m/s^2
Leave a like and mark brainliest if this helped
Leave a like and mark brainliest if this helped
