7.5 × 10¹⁴ Hz is the highest frequency of visible light when wavelengths of visible light range from 400 nm to 700 nm.
The distance a wave travels in one unit of time is known as the wave speed (v).Taking into account that the wave travels one wavelength in one interval,
v=λ/T
Given that T = 1/f, we can write the equation above as,
V = f λ
Given data:
Minimum wavelength of visible light = 400 nm = 4 × 10⁻⁷ m
Speed of light = 3 × 10⁸ m/s
Frequency = c/λ = 3 × 10⁸ / 4 × 10⁻⁷
= 7.5 × 10¹⁴ Hz
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The ground is very large an small amount of electric charge wont affect it
Answer:
d=510.2m
t=10.2s
Explanation:
The formulas for accelerated motion are:
From them we can get 
.
We have:
And substitute:
We multiply both sides by 2a, and continue:
Being d the displacement 
, we have
For our exercise, we will write this as:
And taking upwards direction positive and imposing final velocity 0m/s (for maximum height), we have:
For the time we use:
Answer:
Magnitude = 14 metres
Direction = eastward.
Explanation:
A cross-country skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward.
Whats the Magnitude and Direction?
The magnitude and direction will be the displacement of the cross country skier.
Let the east ward be positive and the west ward be negative.
Since the skier moves 36 meters eastward, then 44meters westward, and finally 22 meters eastward. Then, that will be:
36 - 44 + 22 = 14
Since the answer is positive, the magnitude is 14 and the direction is east ward.
Force required to accelerate 10 kg object to 5.9 m/s/s ?
Mass = 10 kg
Acceleration = 5.9 m/s^2
Force = Mass * Acceleration
Force = 10 kg * 5.9 m/s^2
Force = 59 kg m /s^2 = 59 N
