Answer:
The magnitude of the tension on the ends of the clothesline is 41.85 N.
Explanation:
Given that,
Poles = 2
Distance = 16 m
Mass = 3 kg
Sags distance = 3 m
We need to calculate the angle made with vertical by mass
Using formula of angle



We need to calculate the magnitude of the tension on the ends of the clothesline
Using formula of tension

Put the value into the formula


Hence, The magnitude of the tension on the ends of the clothesline is 41.85 N.
Answer:
625 N
Explanation:
The impulse given to the nail is equal to the change in momentum of the hammer:

where
F is the force exerted by the hammer
is the time of contact
is the mass
is the change in velocity of the hammer
Substituting the data and re-arranging the equation, we can find the force:

Which elements have similar behavior?
Barium, strontium, beryllium.
Answer:
a) Image attached
b) It is acting CW
c) τ = 0.294N.m
Explanation:
As you can see in the image, the ruler will rotate clockwise.
For the total torque: τ = -W*(0.5 - 0.35) The distance used is from 35cm to 50cm
τ = -0.294N.m The magnitude is therefore: 0.294N
Answer:
3054.4 km/h
Explanation:
Using the conservation of momentum
momentum before separation = 5M × 2980 Km/h where M represent the mass of the module while 4 M represent the mass of the motor
initial momentum = 14900 M km/h
let v be the new speed of the motor so that the
new momentum = 4Mv and the new momentum of the module = M ( v + 94 km/h )
total momentum = 4Mv + Mv + 93 M = 5 Mv + 93M
initial momentum = final momentum
14900 M km/h = 5 Mv + 93M
14900 km/h = 5v + 93
14900 - 93 = 5v
v = 2961.4 km/h
the speed of the module = 2961.4 + 93 = 3054.4 km/h