What is the most stable monatomic ion formed from caesium?
1 answer:
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<u>Answer:</u>
The primary product of the photosystem I is NADPH.
<u>Explanation: </u>
NADPH is the acronym of Nicotinamide adenine Dinucleotide Phosphate. This NADPH plays a vital role in many chemical reactions that take place during photosynthesis process. NADPH is released as a product in Photosystem I.
In the photosystem I process, the molecule present will absorb sunlight energy and transfers it to electrons to produce NADPH. This NADPH molecule is used as fuel for the chemical process that occurs during the 2nd stage of the photosynthesis process. Its molecular formula is . It acts as a fundamental metabolite.
Answer:
5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol.
Explanation:
The balanced reaction:
CO (g) + 2 H₂ (g) -> CH₃OH (l)
By stoichiometry of the reaction, the following amounts of moles of each compound participate in the reaction:
- CO: 1 mole
- H₂: 2 moles
- CH₃OH: 1 mole
Being the molar mass of each compound:
- CO: 28 g/mole
- H₂: 1 g/mole
- CH₃OH: 32 g/mole
By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
- CO: 1 mole* 28 g/mole= 28 grams
- H₂: 2 moles* 1 g/mole= 2 grams
- CH₃OH: 1 mole* 32 g/mole= 32 grams
Being 6 kg equivalent to 6000 grams (1 kg= 1000 grams), you can apply the following rules of three:
- If by stoichiometry 32 grams of methanol are formed from 28 grams of carbon monoxide, 6000 grams of methanol are formed from how much mass of carbon monoxide?
mass of carbon monoxide= 5250 grams= 5.25 kg
If by stoichiometry 32 grams of methanol are formed from 2 grams of hydrogen, 6000 grams of methanol are formed from how much mass of hydrogen?
mass of hydrogen= 375 grams
<u><em>5250 grams or 5.25 kg of carbon monoxide and 375 grams of hydrogen are required to form 6 kg of methanol. </em></u>