Question

A homeowner uses a snowblower to clear his driveway. knowing that the snow is discharged at an average angle of 40° with the horizontal, determine the initial velocity v0 of the snow when the dimension a = 19 ft. (round the final answer to two decimal places.)

Answer 1

given that snow is projected at an angle of 40 degree

It range is given as a = 19 ft

$a = 19 * 0.3048 = 5.8 m$

now we can use the formula of horizontal range

$R = \frac{v_o^2 sin2\theta}{g}$

$5.8 =\frac{ v_o^2 sin(2*40)}{9.8}$

$5.8 = \frac{v_o^2 * sin80}{9.8}$

$v_o^2 = 57.7$

$v_o = 7.6 m/s$

so its initial speed must be 7.6 m/s