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2 years ago

8

The maximum centripetal acceleration a car can sustain without skidding out of a curved path is 9.40 m/s2 . If the car is travel

ing at a constant speed of 40.0 m/s on level ground, what is the radius R of the tightest unbanked curve it can negotiate?

1 answer:

AnnyKZ [126]2 years ago

8 0

Answer:

The radius = 170.21 m

Explanation:

The given data are : -

The centripetal acceleration of a car = 9.40 m/s².

Speed of a car = 40.0 m/s .

We have to calculate the radius ( r ) of of curve.

The centripetal acceleration ( a ) is given by

a = $\frac{v^{2} }{r}$

r = $\frac{v^{2} }{a}$ = $\frac{40^{2} }{9.40}$ = $\frac{1600}{9.40}$ = 170.21 m

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