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Leto [7]
3 years ago
8

The maximum centripetal acceleration a car can sustain without skidding out of a curved path is 9.40 m/s2 . If the car is travel

ing at a constant speed of 40.0 m/s on level ground, what is the radius R of the tightest unbanked curve it can negotiate?
Physics
1 answer:
AnnyKZ [126]3 years ago
8 0

Answer:

The radius = 170.21 m

Explanation:

The given data are : -

The centripetal acceleration of a car = 9.40 m/s².

Speed of a car = 40.0 m/s .

We have to calculate the radius ( r ) of of curve.

The centripetal acceleration ( a ) is given by

a = \frac{v^{2} }{r}

r = \frac{v^{2} }{a}  = \frac{40^{2} }{9.40}  = \frac{1600}{9.40} = 170.21 m

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