Question

vinegar contains 5.0g of acetic acid, ch3cooh, in 100.0 ml of solution what is the molarity of acetic acid in vinegar

Answer 1

Answer: 0.83 M

Explanation: Molarity is moles of solute per liter of solution.

Mass of solute(acetic acid) is given as 5.0 g and the volume of solution is 100.0 mL.

We need to convert the grams of acetic acid to moles and for this we divide the grams by molar mass.

Formula of acetic acid is $CH_3COOH$ . Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)  

= 24.02 + 4.04 + 32

= 60.06 grams per mol

moles of acetic acid = 5.0/60.06 = 0.083 moles

Convert mL to L.

we know that, 1 L = 1000 mL

So, to convert mL to L we divide by 1000.

$\frac{100.0}{1000}$ = 0.1000 L

molarity of the solution = $\frac{0.083moles}{0.1000L}$

= 0.83M

So, the molarity of acetic acid in vinegar is 0.83 M.

Answer 2

Find number of moles and divide by volume to get molarity