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3 years ago

Which identifies an oxidation-reduction reaction?

Chemistry

1 answer:

Strike441 [17]3 years ago

8 0

Answer:

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂ → 2CuI + I₂ + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O → CO₂ + H₂

the oxidation state of carbon is +2 on reactant side and on product side it becomes +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄ → Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized

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True or False When one side of a molecule is electronegative (δ-) and the other side of the

lesya [120]

Answer:

True; When one side of a molecule is electronegative (δ-) and the other side of the

molecule is electropositive (δ+), it is said to have a dipole moment.

Explanation:

A dipole moment exists in a molecule as a result of differences in the electronegativity values between the atoms of the elements involved in the chemical bonding.

When a strogly electronegative atom such as oxygen or chlorine is chemically bonded to a less electronegative or an electropositive atom such as hydrogen, there is an uneven sharing of the electrons involved in the bonding. The more electronegative atoms tends to draw the shared electrons mostly to themselves. This induces a partially negative charge (δ-) on them while leaving the electropositive atoms with a partially positive charge (δ+).

Water is an example of a molecule having a dipole moment. The oxygen atoms are more electronegative than hydrogen and as such draw the shared electrons to themselves more, inducing a partial positive charge (δ+) on the hydrogen atoms while they themselves develop a partial negative charge (δ-).

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2 years ago

n-Butane (C4H10) is burned with stoichiometric amount of oxygen. Determine the mole fraction of carbon dioxide and water in the

Fudgin [204]

Answer:

See details below

Explanation:

The balanced reaction equation is given below:

$2C_{4} H_{10}$ + $13O_{2}$ → $8CO_{2}$ + $10H_{2} O$

Mole fraction of CO2 to H20

= 8/10 = $\frac{4}{5}$

Mole ratio of C4H10 to CO2 is 2:8 = 1:4

1 mole of n-butane - 38.12 g

4 moles - ?

= 152.48g fuel consumed.

8 0

3 years ago

How will the volume of a gas be affected if the pressure is tripled, but the temperature remains the same?

dangina [55]

Answer:

Volume of the gass will decrease by three times of the original volume

Explanation:

Volume is inversly propotional to the pressure applied on it.

4 0

3 years ago

Read 2 more answers

How many resonance structures can be drawn for N2O5 (no N-N bond) (minimal formal charge)?

Nezavi [6.7K]

There are approximately 4 resonance structures that can be drawn for N205 (no N-N bond) (minimal formal charge).

8 0

2 years ago

CH4 and CH3CH2CH3 have the lowest boiling points because they experience only \rm CH_4 and \rm CH_3CH_2CH_3 have the lowest boil

ki77a [65]

Answer:

Dispersion forces

Relative molecular mass

Explanation:

Alkanes experience only dispersion forces. Dispersion forces increase with increasevin the relative molecular mass of the compounds. Hence a higher relative molecular mass implies greater dispersion forces and a greater boiling point.

6 0

2 years ago