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makkiz [27]
4 years ago
8

Which identifies an oxidation-reduction reaction?

Chemistry
1 answer:
Strike441 [17]4 years ago
8 0

Answer:

Explanation:

The oxidation reduction reactions are called redox reaction. These reactions are take place by gaining or losing the electrons and oxidation state of elements are changed.

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized.

Na₂CO₃ + H₃PO₄  →  Na₂HPO₄ + CO₂ + H₂O

The oxidation state of carbon on reactant side is +4. while on product side is  also +4 so it neither oxidized nor reduced.

H₂S + 2NaOH → Na₂S + 2H₂O

The oxidation sate of sulfur is -2 on reactant side and in product side it is also -2 so it neither oxidized nor reduced.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized

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What is the mass of oxygen in 3.34 g of potassium permanganate?
3241004551 [841]

Answer:

1.35 g

Explanation:

Data Given:

mass of Potassium Permagnate (KMnO₄) = 3.34 g

Mass of Oxygen: ?

Solution:

First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)

So,

Molar Mass of KMnO₄ = 39 + 55 + 4(16)

Molar Mass of KMnO₄ = 158 g/mol

Calculate the mole percent composition of  Oxygen in Potassium Permagnate (KMnO₄).

Mass contributed by Oxygen (O) = 4 (16) = 64 g

Since the percentage of compound is 100

So,

                        Percent of Oxygen (O) = 64 / 158 x 100

                        Percent of Oxygen (O) = 40.5 %

It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.

So,

for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be

                  mass of Oxygen (O) = 0.405 x 3.34 g

                  mass of Oxygen (O) = 1.35 g

5 0
4 years ago
How to convert Kelvin to degree Celsius? is there any method​
lara [203]

Answer:

{ \tt{kelvin = 273 + celcius \: degree}} \\ { \boxed{ \bf{celcius = kelvin - 273}}}

3 0
3 years ago
Read 2 more answers
During the combustion of NH3, there is an increase in the amount of oxygen present, from 5 to 20 moles while the amount of NH3 r
borishaifa [10]

Explanation:

The ratio of NH3 to NO produced will remain constant since NH3 is the limiting reactant.

Here in this reaction for every 4 moles of ammonia and 5 moles of oxygen gas , 4 moles of NO and 6 moles of water are formed.

So when the amount of oxygen gas is increased to 20 moles without changing the amount of ammonia , the amount of NO formed does not increase as ammonia becomes the limiting reactant.

6 0
3 years ago
Which of the following solutes will lower the freezing point of water the most? NaCl, CaCl2!or AlBr3
MA_775_DIABLO [31]
This uses the concept of freezing point depression. When faced with this issue, we use the following equation:
ΔT = i·Kf·m
which translates in english to:
Change in freezing point = vant hoff factor * molal freezing point depression constant * molality of solution
Because the freezing point depression is a colligative property, it does not depend on the identity of the molecules, just the number of them.
Now, we know that molality will be constant, and Kf will be constant, so our only unknown is "i", or the van't hoff factor.
The van't hoff factor is the number of atoms that dissociate from each individual molecule. The higher the van't hoff factor, the more depressed the freezing point will be.
NaCl will dissociate into Na+ and Cl-, so it has i = 2
CaCl2 will dissociate into Ca2+ and 2 Cl-, so it has i = 3
AlBr3 will dissociate into Al3+ and 3 Br-, so it has i = 4
Therefore, AlBr3 will lower the freezing point of water the most.
6 0
3 years ago
What is sediment and debris, and what role does it play in the way sedimentary rock forms?
defon

Answer:

Sediments are pieces of rock that come from other rocks that were eroded or broken by wind, water or other mechanical forces. Debris are pieces of other materials that were also swept away. 

When these sediments and debris settle, they create layers. These layers are called beds. In time, several layers of other sediments and debris form on top of each other which press down onto the previous layers. Because of the pressure from the weight of the newer layers, the sediments and debris are pressed together and go through cementation. These then produce sedimentary rocks. 

Metamorphic rocks form when rocks undergo heat and pressure. The heat comes from the friction resulting from the pressure. The heat can also come from radioactive decay. The rocks then slowly bake into new rocks called metamorphic rocks. 

Igneous rocks form when magma and lava cool down. Magma is molten fluid found beneath the surface of the Earth. Lava is magma that has reached the surface of the Earth. When they cool down, they crystallize which make igneous rocks. 

The difference between intrusive and extrusive igneous rocks is that one is made beneath the Earth and the other is made on the surface of the Earth. When magma cools, it takes a long time and the product of this cooling are intrusive igneous rocks. On the other hand, extrusive igneous rock is the result of lava cooling, which does not take as long to cool down because it occurs on the surface of the Earth.

Examples of the following types of rocks:

Sedimentary: limestone, sandstone, siltstone

Metamorphic: Marble, gneiss, slate

Igneous: Gabbro (intrusive), granite (Intrusive), obsidian (extrusive)

Explanation:

i used this from somebody

4 0
3 years ago
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