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2 years ago

Select ALL! the solutes below that would be soluble in a polar solvent (like water).

Chemistry

1 answer:

Fofino [41]2 years ago

6 0

Answer:

K2SO4, NH3, HOCI, HCI, CH3NH2, SiCl4, CO2, CH20

Explanation:

Substances are soluble in water when they are ionic or polar covalent substances.

If we look at the substances listed, K2SO4 is ionic while NH3, HOCI, HCI, CH3NH2, SiCl4, CO2, CH20 all contain polar covalent bonds which accounts for their water solubility.

Hence ionic and polar covalent substances are soluble in a polar solvent such as water.

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Answer:

The mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

Explanation:

We are given that

Aqueous solution that contains 22.9% NaOH by mass means

22.9 g NaOH in 100 g solution.

Mass of NaOH(WB)=22.9 g

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Na=23

O=16

H=1.01

Molar mass of NaOH(MB)=23+16+1.01=40.01

Number of moles = $\frac{Given\;mass}{Molar\;mass}$

Using the formula

Number of moles of NaOH $(n_B)=\frac{W_B}{M_B}=\frac{22.9}{40.01}$

$n_B=0.572moles$

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Number of moles of water $(n_A)=\frac{77.1}{18.02}$

$n_A=4.279 moles$

Now, mole fraction of NaOH

= $\frac{n_B}{n_B+n_A}$

$=\frac{4.279}{0.572+4.279}$

=0.882

Hence, the mole fraction of NaOH in an aqueous solution that contain 22.9% NaOH by mass=0.882

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