B
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1) 29.5 N/m
2) 0.100 m
Explanation:
1)
The force constant of the spring can be found by using the fact that the force on the spring is proportional to the extension of the spring (Hooke's Law). Therefore, we can write:
where
is the change in the force on the spring, where
is the force applied when the hanging mass is
is the force applied when the hanging mass is
is the change in extension of the spring, where
is the extension of the spring when the hanging mass is 0.300 kg
is the extension of the spring when the hanging mass is 1.95 kg
Solving for k,
2)
When the first mass is hanging on the spring, we have
where:
is the force applied on the spring (the weight of the hanging mass)
k is the spring constant
is the extension of the spring wrt its natural length
is the natural length of the spring (the unloaded length)
Here we have
k = 29.5 N/m
Solving for , we find:
Answer:
C. Equals
Explanation:
Law of reflection Equals the angle of incidence
Electric power is given by:
Power = voltage x current
10000 = 15.8V
V = 633 Volts
Answer:
1.6×10⁻⁶ N.
Explanation:
From the question,
F = (V/r)q......................... Equation 1
Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.
Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.
Substitute these values into equation 1
F = [(200×10⁶ )/500]×4.0×10⁻¹²
F = 1.6×10⁻⁶ N.
