Vector u :
u = 6 i - 3 j
The magnitude of vector u :
| u | =

Answer:
The magnitude of vector u is 3√5.
Answer
given,
mass of the shell = 87 g = 0.087 Kg
speed of the muzzle = 853 m/s
mass of the helicopter = 4410 kg
A burst of 176 shell fired in 2.93 s
resulting average force = ?
momentum of the shell = m v
= 0.087 x 853
= 74.21 kgm/s
momentum of 176 shell is = 176 p
= 176 x 74.21
= 13060.96
momentum of helicopter = - 13060.96 kgm/s
amount of speed reduce a = 
a= 
a = 2.96 m/s²
velocity = \dfrac{2.96}{2.93}
v = 1.01 m/s
Answer:
The magnitude of the electric field equal to 2.40 N/C at 1.1537m from the wire.
Explanation:
using Guass law,
(guessing that a cylinder of radius r and length L around wire such that wire is at centre )
E. A = qin / e0
E ( 2πr L ) = (1.56 x
x L) / (8.85 x
)
E = (1.56 x
) / (2πr x 8.85 x
)
so 2.40 = (1.54 x
) / (2πr x 8.85 x
)
2.40 (6.284r) = 0.174 x 10²
15.0816r = 17.4
r = 1.1537m