Answer:
Explanation:
The melting point of the solid is 80°C
Vapor point of the liquid is 140°C
What happens to particles of X when heated from 70°C to 85°C?
- Firstly, there would be a phase change from solid to liquid.
- Below the melting point, a substance will exist as a solid.
- With increase in thermal energy inputted by heat, as the temperature climbs above the melting point, it changes to the liquid.
- When the solid begins to heat up, the particles of X starts vibrating about their fixed point.
- At they melting point, they break lose and flow to form a liquid.
- The particles will have more kinetic energy.
KE = 1/2mv^2
m=10 v=3
KE=1/2*10*3^2
KE= 45 Joules
5.00x times 10 ^-4
I’m so sorry if I am wrong
And hope it helped
Answer:
a) variation of the energy is equal to the work of the friction force
b) W = Em_{f} -Em₀
, c) he conservation of mechanical energy
Explanation:
a) In an analysis of this problem we can use the energy law, where at the moment the mechanical energy is started it is totally potential, and at the lowest point it is totally kinetic, we can suppose two possibilities, that the friction is zero and therefore by equalizing the energy we set the velocity at the lowest point.
Another case is if the friction is different from zero and in this case the variation of the energy is equal to the work of the friction force, in value it will be lower than in the calculations.
b) the calluses that he would use are to hinder the worker's friction force and energy
W = Em_{f} -Em₀
N d = ½ m v² - m g (y₂-y₁)
y₂-y₁ = 35 -10 = 25m
c) if there is no friction, the physical principle is the conservation of mechanical energy
If there is friction, the principle is that the non-conservative work is equal to the variation of the energy
yh so fraction are hard so bye